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3 years ago

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2 to the power of 5 over minus 3 equals 2 to the power of 5 over minus 3 equals 2 to the power of 5 over minus 3 equals 2 to the

power of 5 over minus 3 equals 2

1 answer:

nevsk [136]3 years ago

5 0

You are not asking any question. Maybe you want the way how to write it. If so:

2^5/(-3)=2^5/(-3)=2^5/(-3)

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Give a brief explanation as to what kind of solution you expect for the linear equation 18x +1/2 equals 6(3x +25). Transform the

Makovka662 [10]

Answer:

there cannot be any solution of the given linear equation.

Step-by-step explanation:

i) the linear equation of 18x + $\frac{1}{2}$ = 6(3x + 25)

ii) transforming the equation to a simpler form we get

18x + $\frac{1}{2}$ = 18x + 150 which implies that $\frac{1}{2}$ = 150 which is not true.

iii) therefore there cannot be any solution of the given linear equation.

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3 years ago

Needs to be checked.............

Lubov Fominskaja [6]

B. is the correct answer you got it right

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3 years ago

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Can u help me with my work don’t send a link !!!

lisov135 [29]

Answer:

A and C

Step-by-step explanation:

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3 years ago

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a caterpillar stated at point(-2.5 -5.5) on a coordinate plane.She crawled in a straight line through the origin to point (45,y)

iren [92.7K]

Answer:

99

Step-by-step explanation:

Since the caterpillar crawled through the origin, her movement can be described by a straight line equation modeled with the points (-2.5; -5.5) and (0; 0).

The slope of a linear equation is given by:

$m=\frac{y-y_0}{x-x_0}\\m=\frac{-5.5-0}{-2.5-0}\\m=2.2$

For x = 45, the value of y is:

$y= 2.2x\\y= 2.2*45\\y=99$

The value of the y-axis is 99.

3 0

3 years ago

Someone help I don't know what the diameter or radius is

Elenna [48]

<h3><u>Answer:</u></h3>

52.38 inch² & 261.90 inch²

<h3><u>Step-by-step explanation:</u></h3>

Here we need to find the area of the sector . So according to formula we know the area of sector as ,

$\boxed {\sf Area_{(sector)}= \dfrac{\theta}{360}\times \pi r^2 }$

Here we can see that the central angle subtended by the arc is 60° and the radius of the circle is 10 inches . So the required area would be ,

=> Area = ∅/ 360° × π r²

=> Area = 60°/360° × 22/7 × (10in.)²

=> Area = 1/6 * 22/7 * 100 in²

=> Area = 52 .380 in²

<h3><u>★</u><u> </u><u>Hence </u><u>the </u><u>area </u><u>o</u><u>f </u><u>the </u><u>red</u><u> </u><u>sector </u><u>is </u><u>5</u><u>2</u><u>.</u><u>3</u><u>8</u><u> </u><u>inch²</u><u>.</u></h3>

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

Now let's find out the area of blue sector .The angle subtended by the arc will be (360-60)°=300° .

=> Area = 300/360 × 22/7 × 100 in²

=> Area = 261. 90 in²

<h3><u>★</u><u> </u><u>H</u><u>ence </u><u>the </u><u>area </u><u>of </u><u>blue </u><u>sector </u><u>is </u><u>2</u><u>6</u><u>1</u><u>.</u><u>9</u><u>0</u><u> </u><u>inch</u><u>²</u><u>.</u></h3>

$\boxed{\red{\sf Area _{(red \ sector )} = 52.38 in^2 }}$

$\boxed{\blue{\sf Area _{(blue \ sector )} = 261.90 in^2 }}$

5 0

3 years ago