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Simora [160]
3 years ago
11

2 to the power of 5 over minus 3 equals 2 to the power of 5 over minus 3 equals 2 to the power of 5 over minus 3 equals 2 to the

power of 5 over minus 3 equals 2
Mathematics
1 answer:
nevsk [136]3 years ago
5 0
You are not asking any question. Maybe you want the way how to write it. If so:

2^5/(-3)=2^5/(-3)=2^5/(-3)
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Let f(x)=5x3−60x+5 input the interval(s) on which f is increasing. (-inf,-2)u(2,inf) input the interval(s) on which f is decreas
o-na [289]
Answers:

(a) f is increasing at (-\infty,-2) \cup (2,\infty).

(b) f is decreasing at (-2,2).

(c) f is concave up at (2, \infty)

(d) f is concave down at (-\infty, 2)

Explanations:

(a) f is increasing when the derivative is positive. So, we find values of x such that the derivative is positive. Note that

f'(x) = 15x^2 - 60


So,


f'(x) \ \textgreater \  0
\\
\\ \Leftrightarrow 15x^2 - 60 \ \textgreater \  0
\\
\\ \Leftrightarrow 15(x - 2)(x + 2) \ \textgreater \  0
\\
\\ \Leftrightarrow \boxed{(x - 2)(x + 2) \ \textgreater \  0} \text{   (1)}

The zeroes of (x - 2)(x + 2) are 2 and -2. So we can obtain sign of (x - 2)(x + 2) by considering the following possible values of x:

-->> x < -2
-->> -2 < x < 2
--->> x > 2

If x < -2, then (x - 2) and (x + 2) are both negative. Thus, (x - 2)(x + 2) > 0.

If -2 < x < 2, then x + 2 is positive but x - 2 is negative. So, (x - 2)(x + 2) < 0.
 If x > 2, then (x - 2) and (x + 2) are both positive. Thus, (x - 2)(x + 2) > 0.

So, (x - 2)(x + 2) is positive when x < -2 or x > 2. Since

f'(x) \ \textgreater \  0 \Leftrightarrow (x - 2)(x + 2)  \ \textgreater \  0

Thus, f'(x) > 0 only when x < -2 or x > 2. Hence f is increasing at (-\infty,-2) \cup (2,\infty).

(b) f is decreasing only when the derivative of f is negative. Since

f'(x) = 15x^2 - 60

Using the similar computation in (a), 

f'(x) \ \textless \  \ 0 \\ \\ \Leftrightarrow 15x^2 - 60 \ \textless \  0 \\ \\ \Leftrightarrow 15(x - 2)(x + 2) \ \ \textless \  0 \\ \\ \Leftrightarrow \boxed{(x - 2)(x + 2) \ \textless \  0} \text{ (2)}

Based on the computation in (a), (x - 2)(x + 2) < 0 only when -2 < x < 2.

Thus, f'(x) < 0 if and only if -2 < x < 2. Hence f is decreasing at (-2, 2)

(c) f is concave up if and only if the second derivative of f is positive. Note that

f''(x) = 30x - 60

Since,

f''(x) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 30x - 60 \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow 30(x - 2) \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow x - 2 \ \textgreater \  0&#10;\\&#10;\\ \Leftrightarrow \boxed{x \ \textgreater \  2}

Therefore, f is concave up at (2, \infty).

(d) Note that f is concave down if and only if the second derivative of f is negative. Since,

f''(x) = 30x - 60

Using the similar computation in (c), 

f''(x) \ \textless \  0 &#10;\\ \\ \Leftrightarrow 30x - 60 \ \textless \  0 &#10;\\ \\ \Leftrightarrow 30(x - 2) \ \textless \  0 &#10;\\ \\ \Leftrightarrow x - 2 \ \textless \  0 &#10;\\ \\ \Leftrightarrow \boxed{x \ \textless \  2}

Therefore, f is concave down at (-\infty, 2).
3 0
3 years ago
10+(−3.5)×2+(−9)÷(−3)
Zepler [3.9K]

Answer:

6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

10 + (-3.5) × 2 + (-9) ÷ (-3)

<u>Step 2: Evaluate</u>

  1. Multiply:                    10 - 7 + (-9) ÷ (-3)
  2. Divide:                       10 - 7 + 3
  3. Subtract:                   3 + 3
  4. Add:                           6
6 0
2 years ago
Read 2 more answers
Hat is the value of x in the equation 4 x plus 8 y equals 40, when y equals 0.8? 4.6 8.4 10 12
Elan Coil [88]

Step-by-step explanation:

4x + 8y = 40

4x + (8×0.8) = 40

4x + 6.4 = 40

4x = 33.6

4x÷4 = 33.6 ÷ 4

x = 8.4

6 0
3 years ago
If the domain of a function is [1,10), select a point that could be included within the function.
bazaltina [42]
Answer: (1,4)

Explanation: The domain looks at the x coordinates and (1,4) is the only x coordinate in the range given (due to the bracket)
6 0
3 years ago
Read 2 more answers
Renee is buying Halloween candy. She wants to buy candy bars and lollipops and spend no more than $28. Each candy bar costs $0.4
aivan3 [116]

The inequality that represents the possible combinations of candy bars and  lollipops that he can buy is given by:

0.45x + 0.25y \leq 28

<h3>What is the inequality that models this situation?</h3>

The total price can be no more than $28, hence:

T \leq 28

Each candy bar costs $0.45 and each lollipop costs $0.25. x is the number of candy bars and y of lollipops. Hence, the total price is given by:

T = 0.45x + 0.25y.

Hence, the inequality that models the situation is:

0.45x + 0.25y \leq 28

More can be learned about inequalities at brainly.com/question/25235995

6 0
2 years ago
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