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stich3 [128]
3 years ago
13

Which equations are true for x = –2 and x = 2? Select two options x2 – 4 = 0 x2 = –4 3x2 + 12 = 0 4x2 = 16 2(x – 2)2 = 0

Mathematics
1 answer:
Serhud [2]3 years ago
6 0
It is x2-4=0 and 4x 2 = 16

Hope this helps you!!!
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2) If Michael invests $2000 in the bank at a rate of 5.5% for 6 years how much
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Answer:

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Step-by-step explanation:

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2 years ago
What is the factor each expression of x2 - 2x
horrorfan [7]

Answer:

x(x - 2)

Step-by-step explanation:

x² - 2x ← factor out x from each term

= x(x - 2)

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What is the area of the shape below?
mixas84 [53]
76 cm,



(4•10=40)+((10-4)•6)= 76 units
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3 years ago
Find the capacity of the tanks with the following internal dimensions. Express the capacity in cubic meters and liters for each
Vladimir [108]

Step-by-step explanation:

i) Capacity(Volume) = length x breadth x depth

= 3.2 x 2.9 x 1.5

= 13.92 m³

In litres, 13.92 x 1000 = 139,20 litres

ii) Capacity(Volume) = length x breadth x depth

= 2.5 x 1.6 x 1.3

= 5.2 m³

In litres, 5.2 x 1000 = 5200 litres

iii) Capacity(Volume) = length x breadth x depth

= 7.3 x 3.6 x 1.4

= 36.792 m³

In litres, 36.792 x 1000 = 36,792 litres

3 0
3 years ago
A sample of Iron-59 contains 50 mg. One hundred days later, the sample contains 10.75 mg. What is the half-life of iron-59, in d
exis [7]

Answer:

t_{1/2}=45.09 d    

Step-by-step explanation:

We can use the decay equation:

M=M_{0}e^{-\lambda t}

  • M(0) is the initial mass
  • M is the mass after t (1000 days) time
  • λ is the decay constant

But:

\lambda = ln(2)/t_{1/2}

  • t(1/2) is the half-life.

So, we can rewrite the initial equation:

M=M_{0}e^{-\frac{ln(2)}{t_{1/2}}t}

Now, we just need to solve it for t(1/2):

ln(\frac{M}{M_{0}})=-\frac{ln(2)}{t_{1/2}}t

t_{1/2}=-\frac{ln(2)}{ln(\frac{M}{M_{0}})}t

t_{1/2}=-\frac{ln(2)}{ln(\frac{10.75}{50})}100                

t_{1/2}=45.09 d    

I hope it helps you!

5 0
3 years ago
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