Question

Help a brother out lol

Answer 1

We know that $f(x)=3x+1$ and $g(x)=x^2-6$; to find $( \frac{g}{f} )(x)$ we are going to divide $g(x)$ by $f(x)$:
$( \frac{g}{f} )(x)= \frac{x^2-6}{3x+1}$
Since the denoinatorcan't be zero: 
$3x+1 \neq 0$
$x \neq - \frac{1}{3}$

We can conclude that the correct answer is A. $\frac{x^2-6}{3x+1}$  $x \neq - \frac{1}{3}$