Answer:
djdjdjeueueuududhfh ch by by CV
Given

We have to set the restraint

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.
Similarly, we have

So, we have to impose

Squaring both sides, we have

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.
The equation is 2.5(m)+3
<span>Since the ride only costs $3, and for every mile, $2.5 will be charged.</span>
X^2= (x-2[root of x])(x+2[root of x])
think about the 2 and 9 times table
2*-9=-18
2+9=11
Answer: 2 and -9 or -2 and 9