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2 years ago

Find the area of a right triangle with a base of 38 cm and height of 26 cm.

Mathematics

2 answers:

Marianna [84]2 years ago

7 0

Answer:

494cm2

Step-by-step explanation:

Área = (base × height)/2

Área=(38×26)/2=988/2=494cm²

svetlana [45]2 years ago

6 0

Answer:
D.) 494 cm2

Step by Step:
38x26=988
988/2=494

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What is 3 to the power of 8 divided by 3 to the power of 2

Troyanec [42]

Answer:

729

Step-by-step explanation:

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3 years ago

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What is the future value of $500 to be received 3 years from now if the discount rate is 10%?

Shkiper50 [21]

I’m pretty sure it’s $350

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2 years ago

A $450 TV is discounted 10%, and then another 10% a week later. Explain why taking 20% off the original price will not help you

ExtremeBDS [4]

Answer:

Because the price did not stay the same when they discounted it by 10% percent before.

Step-by-step explanation:

10% percent of 450 is 45 so Subtracting that from 450 would give you,405.

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3 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

2 years ago

9y+11z+7y−4z

slava [35]

Answer is 16y + 7z

9y+11z+7y−4z

=9y+11z+7y+−4z

Combine Like Terms:

=9y+11z+7y+−4z

=(9y+7y)+(11z+−4z)

=16y+7z

7 0

2 years ago