Answer:
no. of senior citizens=x
no.of other people=7-x
cost=30=k(7-x)+(k/2)x. k is the cost of a ticket
k(7-x+x/2)
k(7-x/2)-30=0
k=60/(14-x)
now do trial and error substitution for (x<7) until u get a whole number for k also (k<30). if you have the skills you can suggest the number yourself
ie x= 2, k=5$
If you calculate the problem correctly you should end up with:
(A)-(3)
Which equals:
= -3
Hope this helps... have a good day!
Find the total number of tickets sold by multiplying the number of students by the number of tickets each student sold:
23 x 44 = 1012 total tickets.
Each ticket sold for $7, now multiply the total tickets sold by the price of a ticket:
1012 x 7 = $7,084 total money
Answer:
672 ways
Step-by-step explanation:
The total number of ways the friends were supposed to sit without restrictions would have been = 6!
= 720 possible ways.
If the girs should sit on the first or last sit
The possible arrangement= 2!4!
= 2*24
= 48
But now the two girls should be arranged in such a way that the don't sit on either the first or the last chair.
So the possible way now is= way without restriction - way if the girls are to sit at either first or last sit
= 720-48
= 672
