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prisoha [69]
4 years ago
8

Lin is paid $90 for 5 hours of work. She used the following table to calculate how much she would be paid at this rate for 8 hou

rs of work.
amount earned/time worked
-----------------------------
I 90 I 5 I 1/5
I 18 I 1 I
I 144 I 8 I
I I I


Why was the number 1/5 used as a multiplier?
Mathematics
1 answer:
ycow [4]4 years ago
7 0

Answer:

It was used as the multiplier because the 5 represents the hours she's worked. If she uses the 1/5 graph she will find the unit rate of each time she gets paid an hour.

Step-by-step explanation:

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Find all the complex roots. Write the answer in exponential form.
dezoksy [38]

We have to calculate the fourth roots of this complex number:

z=9+9\sqrt[]{3}i

We start by writing this number in exponential form:

\begin{gathered} r=\sqrt[]{9^2+(9\sqrt[]{3})^2} \\ r=\sqrt[]{81+81\cdot3} \\ r=\sqrt[]{81+243} \\ r=\sqrt[]{324} \\ r=18 \end{gathered}\theta=\arctan (\frac{9\sqrt[]{3}}{9})=\arctan (\sqrt[]{3})=\frac{\pi}{3}

Then, the exponential form is:

z=18e^{\frac{\pi}{3}i}

The formula for the roots of a complex number can be written (in polar form) as:

z^{\frac{1}{n}}=r^{\frac{1}{n}}\cdot\lbrack\cos (\frac{\theta+2\pi k}{n})+i\cdot\sin (\frac{\theta+2\pi k}{n})\rbrack\text{ for }k=0,1,\ldots,n-1

Then, for a fourth root, we will have n = 4 and k = 0, 1, 2 and 3.

To simplify the calculations, we start by calculating the fourth root of r:

r^{\frac{1}{4}}=18^{\frac{1}{4}}=\sqrt[4]{18}

<em>NOTE: It can not be simplified anymore, so we will leave it like this.</em>

Then, we calculate the arguments of the trigonometric functions:

\frac{\theta+2\pi k}{n}=\frac{\frac{\pi}{2}+2\pi k}{4}=\frac{\pi}{8}+\frac{\pi}{2}k=\pi(\frac{1}{8}+\frac{k}{2})

We can now calculate for each value of k:

\begin{gathered} k=0\colon \\ z_0=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{0}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{0}{2}))) \\ z_0=\sqrt[4]{18}\cdot(\cos (\frac{\pi}{8})+i\cdot\sin (\frac{\pi}{8}) \\ z_0=\sqrt[4]{18}\cdot e^{i\frac{\pi}{8}} \end{gathered}\begin{gathered} k=1\colon \\ z_1=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{1}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{1}{2}))) \\ z_1=\sqrt[4]{18}\cdot(\cos (\frac{5\pi}{8})+i\cdot\sin (\frac{5\pi}{8})) \\ z_1=\sqrt[4]{18}e^{i\frac{5\pi}{8}} \end{gathered}\begin{gathered} k=2\colon \\ z_2=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{2}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{2}{2}))) \\ z_2=\sqrt[4]{18}\cdot(\cos (\frac{9\pi}{8})+i\cdot\sin (\frac{9\pi}{8})) \\ z_2=\sqrt[4]{18}e^{i\frac{9\pi}{8}} \end{gathered}\begin{gathered} k=3\colon \\ z_3=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{3}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{3}{2}))) \\ z_3=\sqrt[4]{18}\cdot(\cos (\frac{13\pi}{8})+i\cdot\sin (\frac{13\pi}{8})) \\ z_3=\sqrt[4]{18}e^{i\frac{13\pi}{8}} \end{gathered}

Answer:

The four roots in exponential form are

z0 = 18^(1/4)*e^(i*π/8)

z1 = 18^(1/4)*e^(i*5π/8)

z2 = 18^(1/4)*e^(i*9π/8)

z3 = 18^(1/4)*e^(i*13π/8)

5 0
1 year ago
Find cos x if sin x cot x = 0.5
vova2212 [387]

Answer:

cos x = 0.5

Step-by-step explanation:

cot x  = (cos x) / (sin x)

sin x (cot x) = 0.5

cos x = 0.5

7 0
3 years ago
Which factorizations can be used to identify the real zeros of the function f(x)=20x^2+23x-6
Ainat [17]
It’s the quadratic formula because it’s give directly the zeros of a function
5 0
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Mrs. Adenan sold 63 bracelets at one craft fair and 36 bracelets at a second craft fair. Which expression correctly applies the
stellarik [79]
63 + 36...there is a common factor of 9
9(7 + 4) <== this is equivalent

63 + 36...there is a common factor of 3
3(21 + 12)...but this is not an answer choice...but it is equivalent
7 0
4 years ago
How do you estimate the sum of 198,260+31,900?
Vesnalui [34]

To estimate an amount to the tenth we have 3 steps to follow: ...

STEP 2: We add the rounded numbers. ...

STEP 1: Round the summands.

STEP 2: Add the rounded numbers.

STEP 3: Look at the total amount of rounding.

We have rounded the two summands down.

4 0
3 years ago
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