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prisoha [69]
3 years ago
8

Lin is paid $90 for 5 hours of work. She used the following table to calculate how much she would be paid at this rate for 8 hou

rs of work.
amount earned/time worked
-----------------------------
I 90 I 5 I 1/5
I 18 I 1 I
I 144 I 8 I
I I I


Why was the number 1/5 used as a multiplier?
Mathematics
1 answer:
ycow [4]3 years ago
7 0

Answer:

It was used as the multiplier because the 5 represents the hours she's worked. If she uses the 1/5 graph she will find the unit rate of each time she gets paid an hour.

Step-by-step explanation:

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Jerry started doing sit-ups every day. The first day he did 18 sit-ups. Every day after that he did 4 more sit-ups than he had d
USPshnik [31]

Answer:

18 + (4*5) = 38


because 4 * 5 is 20 then 20 + 18 is 38, and that's your answer.



have a nice day!   :)


7 0
3 years ago
Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

7 0
3 years ago
Read 2 more answers
At a bake sale, as student spent $11.00 buying 3 brownies and 5 cookies. His friend spent $3.95 buying 1 brownie and 2 cookies.
dybincka [34]

Answer:

$2.25

Step-by-step explanation:

Let "b" be the price of 1 brownie and "c" the price of 1 cookie.

At a bake sale, a student spent $11.00 buying 3 brownies and 5 cookies. Symbolicaly,

3 b + 5 c = 11.00   [1]

His friend spent $3.95 buying 1 brownie and 2 cookies. Symbolicaly,

1 b + 2 c = 3.95

b = 3.95 - 2c   [2]

If we replace [2] in [1], we get

3 (3.95 - 2c) + 5 c = 11.00

11.85 - 6c + 5c = 11.00

c = 0.85

If we replace c = 0.85 in [2], we get

b = 3.95 - 2 (0.85) = 2.25

8 0
3 years ago
William bought a new sweater at the store when they were having a 45% off sale.
Lady bird [3.3K]
William payed $8.55 at the discount price
5 0
3 years ago
Read 2 more answers
The drama club is selling tickets to its play. An adult ticket costs $15 and a student ticket costs $11. The auditorium will sea
spin [16.1K]

Answer:

83 adult tickets and 217 student tickets.

Step-by-step explanation:

Let number of adult tickets sold = x

Given that total number of tickets = 300

So, number of student tickets = 300 - x

Cost of adult ticket = $15

Cost of student ticket = $11

Total collection from adult tickets = $15x

Total collection from student tickets =  (300-x)\times 11 = 3300-11x

Given that overall collection = $3630

15x+(3300-11x) = 3630\\\Rightarrow 15x-11x=3630-3300\\\Rightarrow 4x = 330\\\Rightarrow   x = 82.5

So, for atleast $3630 collection, there should be 83 adult tickets and (300-83 = 217 student tickets.

Now , collection = $3632

4 0
3 years ago
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