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stiks02 [169]
3 years ago
10

Which of the following represents a constant from the expression given? 15x^2 + 2x + 9

Mathematics
2 answers:
baherus [9]3 years ago
5 0
The correct answer is A
Amiraneli [1.4K]3 years ago
4 0

Answer:

A) 9

Step-by-step explanation:

Hello!

A constant is a fixed and defined number.

A constant is any number that does not have a variable next to it

The only number in the equation that follows this is 9

Hope this Helps!

You might be interested in
20 POINTS WILL MARK AS BRAINLIEST AND SAY THANKS In 2000, the cost of many items increased because the increase in the cost of g
antoniya [11.8K]
Let the cost of gasoline in the year 2000 be represented b the equation
y = a + b*x
where
x = months, counted from January
y = cost, dollars

The given data in the table is
Month:        Jan  Feb  Mar  Apr  May  Jun  Jul  Aug  Sep  Oct  Nov  Dec
x, months:       1       2     3       4      5       6     7      8      9     10     11      12
y, dollars:     ---      ---     ---     ---   1.76   2.13   ---     ---    ---      ---    ---     ---

When x = 5, y = 1.76.
Therefore
a + 5b = 1.76               (1)

When x = 6, y = 2.13
Therefore
a + 6b = 2.13              (2)

Subtract equation (1) from (2).
a + 6b - (a + 5b) = 2.13 - 1.76
b = 0.37

From (1), obtain
a = 1.76 - 5b
   = 1.76 - 5*0.37
   = -0.09

The required equation is
y = 0.37x - 0.09
The graph shows the line, with the given data for May and June.

Answer: D.  y = 0.37x - 0.09

7 0
3 years ago
A ball is dropped from a height of 192 inches onto a level floor. After the third bounce it is still 3 inches off the ground. Pr
ANEK [815]

Answer: The required fraction = \dfrac18

Step-by-step explanation:

Let the required fraction = \dfrac{p}{q}

Given: Initial height = 192 inches

Height of ball after second bounce = \dfrac{p}{q}\times192

Height of ball after third bounce = \dfrac{p}{q}\times\dfrac{p}{q}\times192=192\dfrac{p^2}{q^2}

After the third bounce it is 3 inches off the ground.

So,

(\dfrac{p}{q})^2192=3\\\\\\(\dfrac{p}{q})^2=\dfrac{3}{192}\\\\(\dfrac{p}{q})^2=\dfrac{1}{64}\\\\(\dfrac{p}{q})^2=(\dfrac{1}{8})^2\\\\ \dfrac{p}{q}=\dfrac{1}{8}

Hence, The required fraction = \dfrac18

5 0
3 years ago
15 roses cost 33.75 how much will 27 roses cost​
luda_lava [24]

Answer:

60.75

Step-by-step explanation:

First, you need to see how much one rose costs.

33.75/15 is 2.25

Next, you need to find out how many 27 roses costs.

2.25*27 is 60.75

Now you have your answer.

Hope this helps and is right!

5 0
3 years ago
I need to write an algebraic expression that includes 2 constatants, 2 variables, and 2 different operations. It also need it in
belka [17]

Answer:

An example would be

(x+3)-(y+12)

The two constants are 3 and 12 (I'm assuming you meant "constant" as in the number that stands by itself and not "constatant" lol)

The two variables are x and y

The two operations are addition and subtraction

In words you could say "the quantity of x plus three minus the quantity of y plus twelve"

3 0
3 years ago
What is the relative maximum and minimum of the function?
nevsk [136]
Take the derivitive
f'(x)=3x^2+12x
find where it equals zero
it equal zero at x=0 and x=-4
find the y values
f(0)=-36
f(-4)=-4
the critical points are (0,-36) and (-4,-4)

make sign chart
evalutat f'(x) at x=-5 and x=-1 and x=1, and see their signs
f'(-5)=(+)
f'(-1)=(-)
f'(1)=(+)
see below attachment

max is where sign changes from (+) to (-)
min is where sign changes from (-) to (+)

so
max at (-4,-4)
min at (0,-36)
none of the options are correct, do you have te right problem?

8 0
3 years ago
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