Hello
<span>an equation for the line in point-slope form and general form is :
y = ax+b a : </span>slope ; the <span>Passing through (x' ; y')
</span>y' = ax'+b
y-y' =a(x-x') and : x' =2 y' = - 1
calculate a :
let : y = ax+b .....(D)
....<span>3y-x=7</span>....(D') or y = (1/3)x+7/3
.(D) perpendicular to(D') : slope (D) × slope (D') = -1
slope (D') = 1/3
slop(D)×(1/3) = -1
slope (D) = -3
equation for the line : y-y' =a(x-x')
y+1 =(-3) (x-2)
Plug in numbers. if originally, it was V=1/2 * 1 * 1 * 2=1
<span>tripling the dimensions would be V=1/2 * 3 * 3 * 6=27 </span>
<span>it would be 27 times larger. this could also be found by 3^3, just as doubling would render 2^3
</span>
For a two-tailed test we need to halve 0.01, giving 0.005. Then we need to sutract 0.005 from 0.5, giving 0.5 - 0.005 = 0.495. Looking up the p value of 0.495 in an inverse normal probability table we obtain the value z = 2.5758. Therefore the critical values are -2.5758 and 2.5758.
Answer:
7-(-4)= Positive
-3+(-2)= Negative
5-8= Negative
-10 +12= Positive
Step-by-step explanation:
Your answr is n=8. if this helped plz mark brainliest
