<span>
Let's analyze Hannah's work, step-by-step, to see if she made any mistakes. </span>In Step 1, Hannah wrote

<span> as the sum of two separate derivatives </span>

<span>using the </span><span>sum rule.
</span>
This step is perfectly fine. In Step 2,

was kept as it is, and

was rewritten as

using the constant rule.Indeed, according to the constant rule, the derivative of a constant number is equal to zero.
This step is perfectly fine. In Step 3,

was rewritten as
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supposedly using the constant multiple rule.
The problem is that according to the constant multiple rule,

should be rewritten as
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and not as
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.
<span>
Therefore, Hannah made a mistake in this step.</span>
Answer:
Expand the brackets, and simplify.
(4t - 8/5)-(3-4/3t) = (4t +4/3t) + ( -8/5 - 3) = 5 1/3t - 23/5 = 16/3t - 23/5
5(2t + 1) + (-7t + 28) = 10t + 5 - 7t + 28 = 3t + 33
(-9/2t + 3) + (7/4t + 33) = (-9/2t + 7/4t) + (3 + 33) = -11/4t + 36
3(3t - 4) - (2t + 10) = 9t - 12 - 2t - 10 = 7t - 22
Answer:
B) x^2 - 3/ 3x
Step-by-step explanation:
As, f(x) - g(x) = x/3 - 1/x
So, x^2/ 3x - 3/ 3x
= x^2 - 3/ 3x
<u>Answer:</u>
The correct answer option is C. 13.6 units.
<u>Step-by-step explanation:</u>
Line segment AB was dilated to create the line segment A'B' using the dilation rule
.
We are to find the value of
which is the distance between the twp points A and A'.
For this, we will divide the distance of A'Q by the dilation factor and then subtract the given length.

x =
= 13.6 units