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RSB [31]
3 years ago
7

Which of the following is a halogen?

Chemistry
2 answers:
evablogger [386]3 years ago
8 0

Answer:

\boxed{\mathrm{Iodine}}

Explanation:

Halogens are elements in group 17 or 7 in the periodic table.

Iodine is a halogen.

sashaice [31]3 years ago
4 0

Answer:

iodine

Explanation:

this is the answer on apex

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How many moles would there be in 500,000,000,000 atoms of silver? Show your calculation
atroni [7]

Answer:

Answer: 3.01 * 10^35

Explanation:

500,000,000,000 * 6.02 * 10^23

5 0
3 years ago
ASAP!<br> I have 20 min to finish this i need help
rodikova [14]
The real answer is B
7 0
3 years ago
What is the mass of 10.9 mol Li?<br> Answer in units of g.
Semmy [17]

Answer:

7.57 *10^1 g

Explanation:

10.9 mol Li *6.941 g/1 mol = 75.6569 > 7.57 *10^1 g

6 0
3 years ago
What is the IUPAC name of a bromobenzene with carboxylic acid attached
LuckyWell [14K]

Answer:

Bromobenzoic acid  

Explanation:

COOH has higher priority than Br, so the parent name is benzoic acid.

The COOH group is automatically on C1 of the ring, and the other aromatic carbons are numbered sequentially around the ring.

The name of the substituent is joined to that of the parent, and the locant is attached to that with a hyphen.

The generic IUPAC name is bromobenzoic acid.

There are three isomers of benzoic acid — 2-bromobenzoic acid, 3-bromobenzoic acid, and 4-bromobenzoic acid —  so you must always specify which one you mean.

5 0
3 years ago
A sample of O2(g) is placed in an otherwise empty, rigid container at 4224 K at an initial pressure of 4.97 atm, where it decomp
frutty [35]

Answer:

The value of K_p at 4224 K is 314.23.

Explanation:

O_2(g)\rightleftharpoons 2O(g)

Initially

4.97 atm            0

At equilibrium

4.97 - p               2p

At initial stage, the partial pressure of oxygen gas = =4.97 atm

At equilibrium, the partial pressure of oxygen gas = p_{O_2}=0.28 atm

So, 4.97 - p = 0.28 atm

p = 4.69 atm

At equilibrium, the partial pressure of O gas = p_{O}=2p=2\times 4.69 atm=9.38 atm

The expression of K_p is given as :

K_p=\frac{(p_{O})^2}{(p_{O_2})}

K_p=\frac{(9.38 atm)^2}{0.28 atm}=314.23

The value of K_p at 4224 K is 314.23.

5 0
3 years ago
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