Question

A photon that has an energy of 8.63 × 10^-12 J would emit light at which wavelength (pm)

Answer 1

Answer:The photon will emit light of $2.30\times 10^{-2} pm$.

Explanation:

The energy emitted by the photon,E : $8.63\times 10^{-12} J$

Wavelength of the light emitted by this photon = $\lambda$

$E=\frac{hc}{\lambda }$

h = Planck's constant =$6.626\times 10^{-34} Js$

c = speed of the light =$3\times 10^{8} m/s$

$8.63\times 10^{-12} J=\frac{6.626\times 10^{-34} Js\times 3\times 10^{8} m/s}{\lambda }$

$\lambda=\frac{6.626\times 10^{-34} Js\times 3\times 10^{8} m/s}{8.63\times 10^{-12} J}=2.30\times 10^{-14} m=2.30\times 10^{-2} pm$

$1 m=1\times 10^{12} pm$

The photon will emit light of $2.30\times 10^{-2} pm$.