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NeTakaya
3 years ago
11

When 2,2-dimethylbutane is subjected to free-radical chlorination, ________ distinct monochlorinated products are possible and _

_______ of these contain asymmetric carbon atoms.

Chemistry
1 answer:
malfutka [58]3 years ago
6 0

Answer:

See the explanation

Explanation:

In this case, we have to remember that in the <u>monochlorination products</u> we only have to add one "Cl" with this in mind, we can have several options.

<u>a) 1-chloro-2,2-dimethylbutane</u>

<u>b) (R)-3-chloro-2,2-dimethylbutane</u>

<u>c) (S)-3-chloro-2,2-dimethylbutane</u>

<u>d) 1-chloro-3,3-dimethylbutane</u>

Additionally, from these 4 molecules, we will have 2 enantiomers. (R)-3-chloro-2,2-dimethylbutane and (S)-3-chloro-2,2-dimethylbutane.

See figure 1

I hope it helps!

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What are the formal charges of both chlorines and iodine in icl2?
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Answer:

Explanation:

 Formal charge of ICl₂⁻

Formal charge = group no - ( no of non bonding electrons +no of bonds)

In I there are 7 electrons in outermost orbit . If we add one more electrons due to - ve charge on the ion , it becomes eight . This centrally placed iodine forms two single bond with two chlorine atoms on either side.

Each of chlorine atoms also contains 7 valance electrons like iodine.

So formal charge of chlorine

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 6 + 1 )

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So formal charge of iodine

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 5 + 2 )

=0

 Formal charge of ICl₂⁺

In this case , central iodine will have only 6 valence electrons due to absence one electron.

So formal charge of chlorine in  ICl₂⁺

= group no - ( no of non bonding electrons +no of bonds)

= 7 - ( 6 + 1 )

= 0

formal charge of iodine in  in   ICl₂⁺

7 - ( 4 + 2)

= 1

6 0
4 years ago
What type of ion does neutral produces
Yuki888 [10]

Answer:

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Explanation:

Because they have a neutral charge They can only produce neutrally.

4 0
4 years ago
Which is the BEST evidence that a chemical change has occurred?
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Write a hypothesis:<br> What is the mole ratio of the cation and the anion in a precipitate?
tankabanditka [31]

Answer:

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8 0
3 years ago
CdF2(s)⇄Cd2+(aq)+2F−(aq)A saturated aqueous solution of CdF2 is prepared. The equilibrium in the solution is represented above.
kupik [55]

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The correct answer is option a.

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8 0
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