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zhuklara [117]
3 years ago
8

Calculate the volume in liters of a potassium iodide solution that contains of potassium iodide . Be sure your answer has the co

rrect number of significant digits.
Chemistry
1 answer:
Anna11 [10]3 years ago
6 0

Answer:

23.8 L

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>

<em />

The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:

150 g × (1 mol/166.00 g) = 0.904 mol

0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:

0.904 mol × (1 L/0.0380 mol) = 23.8 L

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3 years ago
A sample of the mineral hematite Iron (III) oxide has a mass of 12.4g. How many moles of the mineral are present?
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Thus problem is providing us with the mass of iron (III) oxide as 12.4 g so the moles are required and found to be 0.0776 mol after the calculations:

<h3>Mole-mass relationships:</h3>

In chemistry, we use mole-mass relationships in order to calculate grams from moles and vice versa. In this case, since we are given the mass of iron (III) oxide as 12.4 g one can calculate the moles by firstly quantifying its molar mass:

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Learn more about mole-mass relationships: brainly.com/question/18311376

8 0
2 years ago
Is a strong acid<br> a. NaC₂H₃O₂ <br> b. HC₂H₃O₂<br> c. KCl <br> d. NH₃<br> e. HCl
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Source:
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3. (see the attached drawing)

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