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zhuklara [117]
3 years ago
8

Calculate the volume in liters of a potassium iodide solution that contains of potassium iodide . Be sure your answer has the co

rrect number of significant digits.
Chemistry
1 answer:
Anna11 [10]3 years ago
6 0

Answer:

23.8 L

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>

<em />

The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:

150 g × (1 mol/166.00 g) = 0.904 mol

0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:

0.904 mol × (1 L/0.0380 mol) = 23.8 L

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A desinfecção

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3 years ago
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zheka24 [161]

Answer:

To gain stability

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What inference can be drawn from the graph?
valina [46]

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Because the reaction favors reactants, their concentration will be higher at equilibrium than the products.

5 0
3 years ago
Read 2 more answers
No links
lukranit [14]

From the calculations, the heat that is required is 2.1 kJ.

<h3>What is the specific heat capacity?</h3>

The term specific heat capacity has to do with the amount of heat that must be supplied to 1Kg of a substance in order to raise its temperature by 1K.

In this case;

H = mcdT

H = 100 grams  * 4.18 J/gC * (25 - 20)

H = 2.1 kJ

Learn more abut specific heat capacity:brainly.com/question/1747943

#SPJ1

7 0
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