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Elan Coil [88]
3 years ago
9

Willie runs 5 miles in 40 minutes. If Willie runs at the same rate, how many miles can he run in 120 minutes?

Mathematics
2 answers:
nydimaria [60]3 years ago
8 0
13 1/2 i think hopefully this helps :)
Andrew [12]3 years ago
8 0
15 Miles. since 120 divided by 40 is 3 and 3 times 5 is 15.
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Solve the system of equations algebraically. Show all of your steps
Katyanochek1 [597]
I am going to explain this using the substitution method, considering it appears to be the best in this situation.

We know (from the bottom equation) that y can equal 3x+20. Using this knowledge, we substitute the y in the top equation for 3x+20. Now, we have an equation that looks like this:

3x+20=x^2+2x

Now we need to move x to one side and then do some radicals (square roots).
Subtract the 2x on the right (since it is smaller, negatives = NONONO), which will give you

x+20=x^2

Now, we take the square root of both sides to get

rad(x+20)=x

Now we have to simplify. 20 doesn't have a square root, but 4 goes into 20, and 4 has a square root of 2. This now becomes

2rad(x+5)

This doesn't simplify any further... we have a problem... no way to isolate x as far as my knowledge goes... Sorry, can't help you any further than that, but another person or your teacher might be able to. R.I.P...
4 0
3 years ago
Evaluate if j = 6: 3] - 10<br><br><br> PLS HELP FAST‼️
OLEGan [10]

Answer:

\sqrt{25}

Step-by-step explanation:

5 0
3 years ago
14. Which of the following linear
Alla [95]
D
Due to the question being the question
8 0
3 years ago
Picture provided help!
weqwewe [10]

Answer:

A -60i - 14j

Step-by-step explanation:

u = -9i + 8j

v = 7i + 5j

2u = 2(-9i + 8j) = -18i + 16j

6v = 6(7i + 5j) = 42i + 30j

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(-18i + 16j) - (42i + 30j)

(-18i - 42i) + (16j-30j)

-60i - 14j

5 0
3 years ago
Given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q
Mamont248 [21]

Answer:

Step-by-step explanation:

From the given information:

a) To express the weekly profit as a function of price

Cost =C(q) = 1500 + 10q

Revenue = p×q = (50 − 0.1q)×q = 50q - 0.1q²

Revenue = 50q - 0.1q²

Weekly profit = Revenue - Cost

P(q) = (50q -0.1q²) - (1500 + 10q)

P(q)= -0.1 q² + 40 q - 1500  

However, q = 500 - 10 p using p = 50 − 0.1q

P= -0.1 (500 - 10 p)² + 40 (500 - 10 p) - 1500

P= -10 p² + 600 p - 6500

b)

The price at which the bottle of the wine must be sold to realise a maximum profit can be determined by finding the derivative and then set it to 0  

P' = 0

= -20p+600 = 0

20p = 600

p = 600/20

p = $30

c)

The maximum profit that can be made by the producer is:

P= -10(30)² + 600(30) - 6500

P = - 9000 + 18000 - 6500

P = $2500

5 0
3 years ago
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