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polet [3.4K]
3 years ago
14

Graph the image of the figure after a dilation with a scale factor of 3 centered at (2, −7). Use the Polygon tool to graph the q

uadrilateral by connecting all its vertices.

Mathematics
1 answer:
allsm [11]3 years ago
4 0

Answer:

Here's what I get.

Step-by-step explanation:

Assume the figure is like Image 1  below.

We must dilate each point by a scale factor of 3 centred at (2, −7).

1. Determine the transformation rules

Each point moves to three times its original distance from the centre.

Let P = a point on the figure and

let O = the centre of dilation

and L = the distance from the point to the centre. Then

L = P - O

Three times that distance is  

3L = 3P - 3O

We want to find the point P' that is 3L from O, so we add this distance to the coordinates of O.

P' = 3L + O = 3P - 3O + O = 3P + 2O

If P is at (x,y) and O is at (h,k), the transformation rule is

(x,y) ⟶ (3x - 2h, 3y - 2k)

2. Make a table of the new coordinates

\begin{array}{cclc}\textbf{Point} & \mathbf{(x,y)} &\textbf{Image Coordinates } \mathbf{(3x - 2h, 3y - 2k)}&\mathbf{(x',y')} \\A & (-2,-7) & (-6,-21) -2(2,-7) = (-6 - 4, -21 + 14) & (-10,-7) \\B & (0,-4) &  (0,-12) -2(2,-7) = (0 - 4, -12 + 14)& (-4,2)  \\C & (3,-3) &  (9,-9) -2(2,-7) = (9 - 4, -9 + 14) & (5,5)  \\D & (4,-5) &  (12,-15) -2(2,-7) = (12 - 4, -15 +14) & (8,-1) \\\end{array}

3. Graph the new shape

You should get a graph like Fig. 2.

The rays from Point O pass through corresponding points in the two shapes, so this is a dilation about O.

Point B is two units left of O and three units up.

Also, B' is six units left and nine units up, so the scale factor is three.

 

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snow_tiger [21]

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Measures are SV=9 units., SY=14 units, YW=\sqrt75units , YW=\sqrt27units

Step-by-step explanation:

Given Y is the circumcenter of ΔSTU. we have to find the measures SV, SY, YW and YX.

As Circumcenter is equidistant from the vertices of triangle and also The circumcenter is the point at which the three perpendicular bisectors of the sides of the triangle meet.

Hence, VY, YW and YX are the perpendicular bisectors on the sides ST, TU and SU.

Given ST=18 units.

As VY is perpendicular bisector implies SV=9 units.

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As vertices of triangle are equidistant from the circumcenter

⇒ SY=YT=UY=14 units

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⇒ YX^2=196-169=27 ⇒ YW=\sqrt27units

Hence, measures are SV=9 units., SY=14 units, YW=\sqrt75units , YW=\sqrt27units





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