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blondinia [14]
4 years ago
10

Write in standard form 60000+80000+10=

Mathematics
1 answer:
fredd [130]4 years ago
4 0
To solve this problem to standard form means adding all those numbers together. 
600,000+80,000= 680,000680,000+10= 680,010
680,010 is your answer
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PLEASE HELP!!!!!
amm1812

Answer:

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If her score were 850 she would pay 1685 per month

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2365 - 1685 = 680  a month more because of the low credit score

6 0
3 years ago
4 x 5 - (2² - 2) =? <br> (18 ÷ 3) + (3² - 7) =?
OverLord2011 [107]
4x5-(2 (2) - 2 ) = 14
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7 0
3 years ago
Yuri thinks that 3/4 is a root of the following function.
sineoko [7]

Given:

The polynomial function is

q(x)=6x^3+19x^2-15x-28

Yuri thinks that \dfrac{3}{4} is a root of the given function.

To find:

Why \dfrac{3}{4} cannot be a root?

Solution:

We have,

q(x)=6x^3+19x^2-15x-28

If \dfrac{3}{4} is a root, then the value of the function at \dfrac{3}{4} is 0.

Putting x=\dfrac{3}{4} in the given function, we get

q(\dfrac{3}{4})=6(\dfrac{3}{4})^3+19(\dfrac{3}{4})^2-15(\dfrac{3}{4})-28

q(\dfrac{3}{4})=6(\dfrac{27}{64})+19(\dfrac{9}{16})-\dfrac{45}{4}-28

q(\dfrac{3}{4})=3(\dfrac{27}{32})+\dfrac{171}{16}-\dfrac{45}{4}-28

q(\dfrac{3}{4})=\dfrac{81}{32}+\dfrac{171}{16}-\dfrac{45}{4}-28

Taking LCM, we get

q(\dfrac{3}{4})=\dfrac{81+342-360-896}{32}

q(\dfrac{3}{4})=\dfrac{-833}{32}\neq 0

Since the value of the function at \dfrac{3}{4} is not equal to 0, therefore, \dfrac{3}{4} is not a root of the given function.

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The expression when m = 43 and n = 6
IrinaVladis [17]

Answer:

What?

Step-by-step explanation:

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The range of the data shown is 0-9 !!
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