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2 years ago

Which of the following is a point where the graph

Mathematics

1 answer:

ser-zykov [4K]2 years ago

7 0

Answer:

-When (2×-5) intersects at ×-axis the value of × will be zero.

=>F(×)=× 0=2×-5

hence,

0,=2×-5

5=2×

=>×=5/2

Step-by-step explanation:

hpe it hlps

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Find the area of the irregular figure. 14 cm 12cm 21 cm 14 cm 16 cm

stiv31 [10]

Answer:

Step-by-step explanation:

Find the area of each shape (rectangle and triangle) and then add the areas together.

Area of rectangle:

A = bh

A = 14*12 = 168 cm2

Area of triangle:

A = 1/2*bh

A = 1/2(16)(21 - 12)

A = 1/2(16)(9)

A = 1/2(144)

A = 72 cm2

Add areas together: (area of the whole shape)

168 + 72 = 240 cm2

8 0

2 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

3 years ago

Can someone help please

Ymorist [56]

Answer:it is 7 and 6 that is your answer if that does not work it is 12 and 13 ok.

8 0

3 years ago

Challenge #1

o-na [289]

Answer:

Translate 10 units right, 9 units up

Step-by-step explanation:

translations simply take the image and move it up or down or side to side, reflections flip the image, dilation changes the dimensions of an image, and rotation rotates an image on its origin point.

8 0

3 years ago

Weights of newborn babies are normally distributed with a mean of 7.452 pounds and

patriot [66]

Answer:

Step-by-step explanation:

8 0

2 years ago