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Ede4ka [16]
3 years ago
10

Scores on an exam are normally distributed with a mean of 76 and a standard deviation of 10. In a group of 230 tests, how many s

tudents score above 96?
Mathematics
2 answers:
worty [1.4K]3 years ago
8 0
We are given with a mean of 76 and a standard deviation of 10. IN this case, we are asked to determine the probability that the score is beyond 96. 

z score = (96-76)/ 10 = 2

With the z-score of 2, the probability that is equivalent is 0.0235 or 2.35 percent. 
Tanzania [10]3 years ago
5 0
The score of 96 is 2 standard deviations above the mean score. Using the empirical rule for a normal distribution, the probability of a score above 96 is 0.0235.
Therefore the number of students scoring above 96 is given by:
230\times 0.0235=5\ students
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The junior and senior students at Mathville High School are going to present an exciting musical entitled, "Math, What is it Goo
xeze [42]

Some parts are missing in the queston. Find attached the picture with the complete question

Answer:

                   \large\boxed{\large\boxed{161}}

Explanation:

Let's put the information in a table step-by step.

                                                (number of remaining students)

                                                        Juniors          Seniors

Condition

  • Initially                                           J                     S
  • 15 seniors left                                                   S - 15
  • Twice juniors as seniors         2(S - 15)
  • 3/4 of the juniors left              1/4×2(S - 15)
  • 1/3 of seniors left                                             2/3×(S - 15)

At the end, there were 8 more seniors than juniors:

  • 2/3×(S - 15) -  1/4×2(S - 15) = 8

Now you have obtained one equation, which you can solve to find S, the number of senior students, and then the number of junior students.

Solve the equation:

2/3\times (S - 15) -  1/4\times 2(S - 15) = 8

  • Mutilply all by 12:

8(S - 15)-6(S - 15)=96

  • Distribution property:

8S-120-6S-90=96

  • Addtion property of equalities:

8S-6S=96+120+90

  • Add like terms:

2S=306

  • Division property of equalities:

S=306/2=153

That is the number of senior students that came out to the information meeting, but the number of students remaining to perform in the school musical is (from the table above):

2/3\times (S-15)+1/4\times 2(S-15)

Just substitute S with 153 fo find the number of students that remained to perfom in the musical:

          2/3\times (153-15)+1/4\times 2(153-15)\\ \\ 2/3(138)+1/2(138)

          161

5 0
3 years ago
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