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3 years ago

11

In the room there are 5 big boxes. In each box there are 3 smaller boxes. In each of these small boxes the are 4 smaller boxes.H

ow many boxes of different sizes are there in the room?

1 answer:

Masja [62]3 years ago

5 0

Answer:

Step-by-step explanation

there are 80 boxes in total

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Plzz HELP FOR POINTS AND BRAINLIST ANSWER

storchak [24]

A)Plugging in our initial statement values of y = 16 when x = 10, we get:

16 = 10k

Divide each side by 10 to solve for k:

16/10=

k = 1.6

Solve the second part of the variation equation:

Because we have found our relationship constant k = 1.6, we form our new variation equation:

y = 1.6x

Since we were given that x, we have

y = 1.6()

y = 0

B)Plugging in our initial statement values of y = 1 when x = 15, we get:

1 = 15k

Divide each side by 15 to solve for k:

1/15

=15k

k = 0.066666666666667

7 0

3 years ago

A formal garden has 3 sections of different colored tulips. Each section has 162 tulips.

Anettt [7]

486 if your looking for the total

3 0

3 years ago

What’s the correct answer for this?

grigory [225]

Answer:

The answer is 20

Step-by-step explanation:

Reasoning it is correct because for questions like this the bottom numbers for each shape are 10 and 8 they are very close to each other on the number line there fore since the number is two off you subtract 2 and then two again since it is 2 off to get 21 the closest answer is 20

It is a little confusing but since it is two places off you subtract two twice

8 0

3 years ago

Write<br> 9/18<br> in lowest terms

kogti [31]

Answer:

1/2

Step-by-step explanation:

7 0

3 years ago

Need help please!!!!

ArbitrLikvidat [17]

Given : A inequality is given to us . The inequality is 19 ≥ t + 18 ≥ 11 .

To Find : The correct option between the given ones . To write the compound inequality with integers .

Solution : The given inequality to us is 19 ≥ t + 18 ≥ 11 . Let's simplify them seperately .

$\red{\tt Case\:1}$

⇒ 19 ≥ t + 18 .

⇒ t + 18 ≤ 19 .

⇒ t ≤ 19 - 18 .

⇒ t ≤ 1 = 1 ≥ t . ..................(i)

$\red{\tt Case\:2}$

⇒ t + 18 ≥ 11 .

⇒ t ≥ 11 - 18.

⇒ t ≥ -7 . ....................(ii)

<u>On</u><u> </u><u>combing</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>&</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>.</u>

$\Large\boxed{\green{\bf \red{\longmapsto} 1 \geqslant t \geqslant -7 }}$

This means that t is less than or equal to 1 but greater than or equal to (-7) .

4 0

3 years ago