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kipiarov [429]
3 years ago
11

In the room there are 5 big boxes. In each box there are 3 smaller boxes. In each of these small boxes the are 4 smaller boxes.H

ow many boxes of different sizes are there in the room?
Mathematics
1 answer:
Masja [62]3 years ago
5 0

Answer:

Step-by-step explanation

there are 80 boxes in total

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A number cube was rolled as part of an experiment. The results are shown in the table. Explain how to find the experimental prob
pychu [463]

The experimental probability of rolling a 6 is 9/60  which can be determined by dividing the frequency of the observation 6 with the total frequency of the experiment.

<u>Step-by-step explanation:</u>

Experimental probability is different from theoretical probability because the former is obtained by experimentation  while the latter is what we expect theoretically.When we take a number of observations, the experimental probability and theoretical probability need not be the same.

In this question we have to determine the experimental probability of 6. It can be determined by dividing the frequency of the observation 6 by the total frequency of the experiment.

frequency of 6=9

total frequency=frequency of 1+frequency of 2+frequency of 3+frequency of 4+frequency of 5+frequency of 6

=13+11+9+8+10+9

=60

P(6)=frequency of 6/total frequency

=9/60

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Gwar [14]
A) 15/4 = 4/4+4/4+4/4+3/4= 3 3/4
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c = 26/12 = 12/12 + 12/12 + 2/12 =  2 2/12
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If the volume of a box is 2x3 + 4x2 − 30xwhich of the dimensions are possible with the given x-value?
Kipish [7]

The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

Step-by-step explanation:

The given is,

                        2 x^{3} + 4 x^{2} -30x................................(1)

Step:1

    Check for option A,

             x = 1, dimensions 8 by 9 by 1  

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(2)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                     = 72............................................(3)

            From equation (2) and (3)

                                -24 ≠ 72

            So, X=1; dimensions 8 by 9 by 1 is not possible.

   Check for option B,

             x = 1, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(4)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30.........................................(5)

            From equation (4) and (5)

                                -24 ≠ 30

            So, X=1; dimensions 2 by 5 by 3 is not possible.

   Check for option C,

            x = 4, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72.............................................(6)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30............................................(7)

            From equation (6) and (7)

                               72 ≠ 30

            So, X=4; dimensions 2 by 5 by 3 is not possible.

    Check for option C,

            x = 4, dimensions 8 by 9 by 1

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72............................................(8)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                    = 72............................................(9)

            From equation (8) and (9)

                               72 = 72

            So, X=4; dimensions 8 by 9 by 3 is possible.

Result:

           The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

         

4 0
3 years ago
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