Answer:
Midpoint is ( Average of x’s, Average of y’s )
1 = (x + 7)/2
2 = x + 7, x = - 5
and - 1 = (y + (-4))/2
so - 2 = y - 4 and y = 2
Pt B = (- 5, 2)
-2(y-3)=22
-2y+6=22
-2y=16
y=-8
Answer:
204/841
Step-by-step explanation:
17/29 times 12/29
Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
