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Anni [7]
4 years ago
5

THIS IS WORTH 17 POINTS Question 1: Picture Question 2: Picture

Mathematics
1 answer:
QveST [7]4 years ago
3 0
Question #1:

The surface area of a prism is the area of the outside of the prism, the volume is how much the inside of the container holds.

Let's find the volume and surface area of the prism given.

V = lwh

Plug in what we know:

V = (18.4)(10.9)(8.7)

Multiply:

V = <span>1744.872 m^3

SA = </span>2<span>(<span><span><span>wl </span>+ <span>hl </span></span>+ <span>hw</span></span><span>)

Plug in what we know:

SA = 2((10.9)(18.4) + (8.7)(18.4) + (8.7)(10.9))

Multiply:

SA = 2(200.56 + 160.08 + 94.83)

Add:

SA = 2(455.47)

Multiply:

SA = 910.94 m^2

Now find the difference:

</span></span>Note that these are different measurements.

The volume is measured in cubic meters and the surface area is measured in square meters.

910.94 m^2 = 27493.793 m^3

Find the difference:

27493.793 m^3 - 1744.872 m^3 = 25748.921

Question #2:

The formula for the surface area of a rectangular prism is:

SA = 2(wl + hl + hw)

Plug in what we know:

SA = 2((5)(6) + (3)(6) + (3)(5))

This is the equation we use to find the surface area of this figure.

Multiply:

SA = 2(30 + 18 + 15)

Add:

SA = 2(63)

Multiply:

SA = 126 cm^2
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harkovskaia [24]
y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\&#10;y''(0)=20\cdot0^3=0

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3 years ago
What is the slope of this line?<br> -1/5<br> 1/5<br> 5<br> -5
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Answer:

1/5

Step-by-step explanation:

The slope of a line at any given point is Rise/run

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3 years ago
Points A(-2, 4, 8(1.3), C(4, -1) and D form a parallelogram. What are the coordinates of D9
Sholpan [36]

Answer:

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Step-by-step explanation:

Mark the given points in the coordinate system (look at the picture).

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D(7, -2)

Look at the other pictures

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The vectors AB and DC are congruent and the vectors BC and AD are congruents too.

If a vector ,< a, b > is congruent to a vector < c, d >, then a = c and b = d.

The formula of coordinates of the vetror:

< x₂ - x₁, y₂ - y₁ >

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vector DC = < 4 - x, -1 - y >

vector BC = < 4 - 1, -1 - 3 > = < 3, -4 >

vector AD = < x - (-2), y - 4 > = < x + 2, y - 4 >

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BC = AD ⇒ x + 2 = 3 and y - 4 = -4 ⇒ x = 1 and y = 0

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