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hammer [34]
3 years ago
6

Need help ASAP please!!! The formula determines the magnitude of an earthquake, where I is the intensity of the earthquake and S

is the intensity of a “standard earthquake.” How many times stronger is an earthquake with a magnitude of 8 than an earthquake with a magnitude of 6? Show your work.
Mathematics
1 answer:
snow_lady [41]3 years ago
5 0

Answer:

100

Step-by-step explanation:

M = log(I/S)

The intensity of the first earthquake:

8 = log(I₁/S)

10⁸ = I₁/S

I₁ = 10⁸ S

The intensity of the second earthquake:

6 = log(I₂/S)

10⁶ = I₂/S

I₂ = 10⁶ S

The ratio is:

I₁/I₂ = (10⁸ S) / (10⁶ S)

I₁/I₂ = 100

It is 100 times stronger.

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Westkost [7]

Answer:

B

Step-by-step explanation:

2(x)+4=16

2(6)+4=16

12+4=16

7 0
3 years ago
If A and B are mutually exclusive events, then P(A or B) = P(A) + P(B).
Korolek [52]

Answer:

P(A or B) = 25%

Step-by-step explanation:

P(A and B) = 30%

P(A) = 40%

P(B) = 15%

Apply given formula:

P(A or B) = P(A) + P(B) - P(AB)

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= 25%

8 0
3 years ago
Someone with the right answer help me
andre [41]

Answer:

46 degrees.

Step-by-step explanation:

Sin(angle) = 5/7. Using a calculator, this angle is thus 45.6, or approximately 46 degrees.

5 0
3 years ago
How many different 5-digit pins are there where none of the digits are repeated?
vazorg [7]
<span>With no digit being repeated: 10*9*8*7*6= 30,240</span>
7 0
3 years ago
What is the m?<br> -8 + 4m = 2
IgorLugansk [536]
Exact Form : 5/2
Decimal Form : 2.5
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