When managing visibility at an intersection, you should scan for?

a paratrooper jumps out of a plane and opens her parachute shortly afterward. 10 seconds later the upward force on the parachute

Flura [38]

Answer:

Acceleration = 2.45 m/s²

Explanation:

The resultant vertical force on the paratrooper = ma = upward force - total weight of both the parachute and the

Ma = W - Fu .............. Equation 1

Where Fu = upward force on the parachute, W = combined Weight of the parachute and the paratrooper

W = Mg......................... Equation 2

Making M the subject of formula

M = W/g...................... Equation 3

Where M = combined mass of the parachute and the paratrooper, g = acceleration due to gravity.

Given: W = 800 N, g = constant = 9.8 m/s²

Substituting these values into equation 3

W = 800/9.8

W = 81.63 kg.

Also Given: Fu = 600 N, W = 800 N

Substituting these values into equation 1

81.63a = 800 - 600

81.63a = 200

Dividing both side of the equation by the coefficient of a

81.63a/81.63 = 200/81.63

a = 2.45 m/s²

Therefore acceleration = 2.45 m/s²

3 0

3 years ago

Earth reads 650N what is your mass

sesenic [268]

P = m . g
650 = m.10
m = 650/10
m = 65 kg

7 0

3 years ago

A monkey drops a banana (straight down) from a branch 40 m off of the ground. How long will the banana be in air?

nasty-shy [4]

What do you mean 40 m ?? I was trying to solve it, but it’s kinda confusing

3 0

3 years ago

An electron with an initial speed of 5.00××1055 m/s enters a region in which there is an electric field directed along its direc

Hitman42 [59]

Answer:

7.90 N/C

Explanation:

Given:

$u$ = initial velocity of the electron = $5\times 10^5\ m/s$

$v$ = final velocity of the electron = 0 m/s

$x$ = distance traveled by the electron before coming to rest = 9 cm = 0.09 m

Assume:

$e$ = charge on an electron = $1.6\times 10^{-19}\ C$

$m$ = mass of an electron = $9.1\times 10^{-31}\ kg$

$E$ = electric field along the direction of motion

$F$ = electric force on the electron

$W$ = work done by the electric force

Since the electron is moving in the direction of the electric field, then the electric force on it will act in the direction opposite to its displacement whose magnitude is given by:

$F = eE$

Since the displacement of the electron opposite to the direction of electron, the work done by electric force will be given by:

$W = - Fx\\\Rightarrow W = -eEx$

Since the electron enters the region of the uniform electric field with an initial speed u and travels a distance x to come to rest. The change in kinetic energy of the electron can be given by:

$\Delta K = \dfrac{1}{2}m(v^2-u^2)\\\Delta K = \dfrac{1}{2}m((0)^2-u^2)\\\Delta K = -\dfrac{1}{2}mu^2\\$

Since only the electric force is doing work on the electron, then the change in kinetic energy will be equal to the work done by electric force. This is due to the work-energy theorem.

$\therefore \Delta K = W\\\Rightarrow -\dfrac{1}{2}mu^2=-eEx\\\Rightarrow \dfrac{1}{2}mu^2=eEx\\\Rightarrow E=\dfrac{mu^2}{2ex}\\\Rightarrow E=\dfrac{9.1\times 10^{-31}\times (5\times 10^{5})^2}{2\times 1.6\times 10^{-19}\times 0.09}\\\Rightarrow E=7.90\ N/C$

Hence, the magnitude of electric field is given 7.90 N/C which point in the direction of the displacement of the electron.

8 0

4 years ago

Displacement includes both distance and direction. a. true b. false

Novay_Z [31]

Answer:

True

Explanation:

Displacement can be considered as a distance with direction when an object moves in straight line. Distance is a scalar quantity which means it has only magnitude but lack of direction. Magnitude basically means how far or how long from the initial startup (e.g 7 km) is magnitude.

On the other hand, displacement is a vector quantity which means it has both magnitude and direction. We can use a symbol of negative and positive to determine the direction. Generally, up is positive; down is negative; west is negative and east is positive but it depends on some case where down can be positive (e.g projectile motion) but you can specify or modify how you want your direction to be, make sure to calculate it right though.

Displacement means changes in position which can be expressed as $\displaystyle{p_2 -p_1}$ where $\displaystyle{p_2}$ is final position/destination and $\displaystyle{p_1}$ is initial position/destination. Displacement does include distance but maybe not total distance if we go for a right-triangle distance. However, displacement includes total distance if an object moves in a straight point. (e.g moving to 20 km straight) - both distance and displacement are same in this case.

4 0

2 years ago