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4 years ago

An object with a mass of 20 kg has a net force of 80 N acting on it. What is the acceleration of the object?

Physics

2 answers:

Nikitich [7]4 years ago

4 0

Answer:

The acceleration of the object is 4 m/s²

Explanation:

Newton's Second Law, also called the Fundamental Law of Dynamics, indicates that: "The change of motion is directly proportional to the printed driving force and occurs along a straight line along which that force is printed." This means that the acceleration of a moving object depends on the amount of force applied at a given time, in order to modify its trajectory or speed.

In summary, this law establishes that the net force applied to a body is proportional to the acceleration that body acquires. The constant of proportionality is the mass of the body, and this law can be expressed as:

F = m * a

where:

F=Force
m=mass
a=acceleration

In this case it is necessary to know the acceleration, then:

$a=\frac{F}{m}$

An object with a mass of 20 kg has a net force of 80 N acting on it. So,

F= 80 N
m= 20 kg

Replacing:

$a=\frac{80 N}{20 kg}$

Knowing that N is a unit of measure that is obtained as kg * m/s²:

a= 4 m/s²

The acceleration of the object is 4 m/s²

inysia [295]4 years ago

3 0

Answer:

2 ) $4 ms^{-2}$

Explanation:

By Applying Newton's second law of motion

Force = mass * acceleration

$acceleration=\frac{force}{mass} \\=\frac{80}{20} \\= 4 ms^{-2}$

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Jenny was applying her makeup when she drove into the student parking lot last Friday morning . Unaware that Cheryl was stopped

Akimi4 [234]

Answer: F = 102141N

Explanation: Newton's 2nd Law states that a force can change the motion of a body. The relation is given by

F = m.a

whose units are:

[F] = N

[m] = kg

[a] = m/s²

Jenny's car, at the moment of the break, had acceleration:

$a=\frac{\Delta v}{\Delta t}$

$a=\frac{11}{0.14}$

a = 78.57 m/s²

Then, Force is

F = 1300*78.57

F = 102141 N

Jenny's car experienced a force of magnitude 102141N.

6 0

3 years ago

A squirrel is trying to locate some nuts he buried for the winter. He moves 4.3 m to the right of a stone and dogs unsuccessfull

krek1111 [17]

Answer:

The total displacement from the starting point is 1.5 m.

Explanation:

You need to sum and substract, depending on the movement (to the right, sum; to the left, substract).

First, it moves 4.3 m right and return 1.1 m. So the new distance from the starting point is 3.2 m.

Second, it moves 6.3 m right, so the new distance is 9.5 m.

Finally it moves 8 m to the left, so 9.5 m - 8 m= 1.5 m.

Summarizing, at the end the squirrel is 1.5 m from its starting point.

8 0

4 years ago

Define torque qualitatively and quantitatively

andrezito [222]

The rotational effect of a force is called torque.it is the cause of rotation or angular deceleration

τ=rXF
where
τ = F r sin @
hope it helps

4 0

3 years ago

Estimate the acceleration due to gravity at the surface of Europa (one of the moons of Jupiter) given that its mass is 4.9×1022k

Taya2010 [7]

Answer: $g=1.97 m/s^2$

Explanation:

Given

mass of Jupiter is $M=4.9\times 10^{22} kg$

Density of Jupiter is same as Earth

$density\ of\ Earth=density\ of\ Jupiter=5510 kg/m^3$

$mass=volume\times density$

considering Jupiter to be sphere of radius r

$M=\frac{4}{3}\times \pi r^3\times \rho$

$r^3=\frac{3M}{\rho \times 4\pi}$

$r^3=\frac{3\times 4.9\times 10^{22}}{5510\times 4\pi}$

$r=(\frac{3\times 4.9\times 10^{22}}{5510\times 4\pi})^{\frac{1}{3}}$

$r=1.28\times 10^6 m$

acceleration due to gravity is given by

$g=\frac{GM}{r^2}$

$g=\frac{6.67\times 10^{-11}\times 4.9\times 10^{22}}{(1.28\times 10^6)^2}$

$g=1.97 m/s^2$

3 0

4 years ago

Calculate the frequency of visible light having a wavelength of 410 nm

maria [59]

Given: Wavelength λ = 410 nm convert to Meters m = 4.10 x 10⁻⁷ m

Speed of light c = 3 x 10⁸ m/s

Required: Frequency f = ?

Formula: c = λf

f = c/λ

f = 3 x 10⁸ m/s/4.10 x 10⁻⁷ m

f = 7.32 x 10¹⁴/s or 732 Thz (Terahertz)

6 0

4 years ago