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Blababa [14]
3 years ago
14

What is the product of (6x3+3x)(x2+4)

Mathematics
1 answer:
ki77a [65]3 years ago
3 0
If you would like to know what is the product of (6 * x^3 + 3 * x) * (x^2 + 4), you can calculate this using the following steps:

(6 * x^3 + 3 * x) * (x^2 + 4) = 6 * x^3 * x^2 + 6 * 4 * x^3 + 3 * x * x^2 + 3 * 4 * x = 6 * x^5 + 24 * x^3 + 3 * x^3 + 12 * x = 6 * x^5 + 27 * x^3 + 12 * x

The correct result would be 6 * x^5 + 27 * x^3 + 12 * x.
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Answer:

D: 20h + 45 = 165

Step-by-step explanation:

20 for EACH hour means that there's a variable (h) attached to 20 so it has to be 20h

Because of that, we can eliminate choices A and B.

Charges mean that it's ADDED to the price so it has to be 45 PLUS 20h

20h + 45 = 165

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3 years ago
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25-1/2=

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5 + 3 - c (when c=8)
ludmilkaskok [199]

Answer:

0 is your answer

Step-by-step explanation:

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8 0
3 years ago
I don’t understand the polynomials
Serhud [2]
Polynomial comes from poly- (meaning "many") and -nomial (in this case meaning "term") ... so it says "many terms"

A polynomial can have:

constants (like 3, −20, or ½)
variables (like x and y)
exponents (like the 2 in y2), but only 0, 1, 2, 3, ... etc are allowed
that can be combined using addition, subtraction, multiplication and division ...

... except ...

... not division by a variable (so something like 2/x is right out)

So:

A polynomial can have constants, variables and exponents,
but never division by a variable.

Also they can have one or more terms, but not an infinite number of terms.

These are polynomials:

3x
x − 2
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(Yes, "5" is a polynomial, one term is allowed, and it can be just a constant!)



These are not polynomials

3xy-2 is not, because the exponent is "-2" (exponents can only be 0,1,2,...)
2/(x+2) is not, because dividing by a variable is not allowed
1/x is not either
√x is not, because the exponent is "½" (see fractional exponents)


But these are allowed:

x/2 is allowed, because you can divide by a constant
also 3x/8 for the same reason
√2 is allowed, because it is a constant (= 1.4142...etc)
7 0
3 years ago
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