All categories

3 years ago

What is 78.867 ÷0.9 ANSWER FAST!!

Mathematics

2 answers:

xeze [42]3 years ago

4 0

Answer:87.63

Step-by-step explanation:

Dafna1 [17]3 years ago

3 0

Answer:

87.63

Step-by-step explanation:

You might be interested in

Alisa has a bunch of coins. She has pennies. She has nickels. She has dimes. She has quarters. They lie in one big pile. Alisa w

Alona [7]

Answer:

E. Not enough info.

Step-by-step explanation:

There could be 2 quarters 500 nickels and 7 pennies or 800 pennies 50 quarters and 2 nickels.

3 0

3 years ago

Read 2 more answers

How many units long is a segment whose endpoints are (2,3) and (7,15)?

Ahat [919]

Answer:

13 units

Step-by-step explanation:

Distance formula: $d = \sqrt{(x2-x1)^2 + (y2-y1)^2}$

Simply plug in your variables

$d = \sqrt{(7-2)^2 + (15-3)^2}$

$d = \sqrt{5^2 + 12^2}$

$d = \sqrt{25 + 144}$

$d = \sqrt{169}$

d = 13

5 0

3 years ago

G is proportional to the square of t. If t=2 and g=64, find g when t=3.5.

choli [55]

$If\ g\ is\ proportional\ to\ the\ t^2\ we\ have\ proportion\\\\
g=64\ \ \ \ ---\ \ \ t^2=2^2=4\\\\\
g=?\ \ \ ----t^2=(3,5)^ 2=12,25\\\\
4g=64*12,25\\\\
4g=784\ \ |:4\\\\g=196\\\\ Answer\ is\ g=196\ for\ t=3,5.$

4 0

3 years ago

What would my GPA be? Here are my grades.

marta [7]

That is approximately, in order, a C, a C, a B, a D, an A, a B, and an A.

In grade points that is a 2, a 2, a 3, a 1, a 4, a 3, and a 4.

The average of those numbers is about 2.7, so you have a 2.7.

You can raise that by bringing up the D as it is an outlier here.

4 0

3 years ago

Find the exact value of cos theta, given that sin thetaequalsStartFraction 15 Over 17 EndFraction and theta is in quadrant II.

vova2212 [387]

Answer:

$cos \theta = -\frac{8}{17}$

Step-by-step explanation:

For this case we know that:

$sin \theta = \frac{15}{17}$

And we want to find the value for $cos \theta$ , so then we can use the following basic identity:

$cos^2 \theta + sin^2 \theta =1$

And if we solve for $cos \theta$ we got:

$cos^2 \theta = 1- sin^2 \theta$

$cos \theta =\pm \sqrt{1-sin^2 \theta}$

And if we replace the value given we got:

$cos \theta =\pm \sqrt{1- (\frac{15}{17})^2}=\sqrt{\frac{64}{289}}=\frac{\sqrt{64}}{\sqrt{289}}=\frac{8}{17}$

For our case we know that the angle is on the II quadrant, and on this quadrant we know that the sine is positive but the cosine is negative so then the correct answer for this case would be:

$cos \theta = -\frac{8}{17}$

5 0

3 years ago