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andriy [413]
3 years ago
10

No need of a answer anymore.

Mathematics
1 answer:
Rom4ik [11]3 years ago
5 0

Answer:

mean score of class B = 1778/25 = 71.12

Step-by-step explanation:

This was your question : Class A has 12 pupils and class B has 25 pupils. Both classes sit the same maths test. The mean score for class A is 80. The mean score for both classes is 74. What is the mean score (rounded to 2 DP) in the maths test for class B?

mean of class A = Σfx/Σf

mean of class A =  80

Σfx = 80 × 12 = 960

Mean score for both classes = 74

where

b = Σfx  of class B

960 + b/37 = 74

cross multiply

960 + b = 2738

b = 2738 - 960

b = 1778

mean score of class B = Σfx/Σf

Σfx = 1778

Σf = 25

Therefore,

1778/25 = 71.12

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Which number is rational?
marishachu [46]

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Evaluate: <br><br>6-(2/3)^2<br><br>A. 17/3<br>B. 52/3<br>C. 49/9<br>D. 50/9​
Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

<u>....................................................................................................................................</u>

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations!  :)

\dag\textsf{Acronym \: PEMDAS}

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is \mathsf{6-(\cfrac{2}{3})^2}

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain  \mathsf{6-\cfrac{4}{9}}.

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: \mathrm{\cfrac{6}{1}-\cfrac{4}{9}}. Now let's multiply the denominator and the numerator of the first fraction times 9: \mathrm{\cfrac{54}{9}-\cfrac{4}{9}}.

See, now the fractions have the same denominator. All we should do now is subtract the numerators: \mathrm{\cfrac{50}{9}}.

∴, the answer is Option D.

Hope this helped you out, ask in comments if any queries arise.

Best Wishes!

\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach \: far. Aim \: high. Dream \: big.}}}}}\bigstar\star

\underline{\rule{300}{5}}

5 0
2 years ago
Read 2 more answers
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