Answer:
We need at least 243 stores.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error of the interval is:
For this problem, we have that:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Determine the number of stores that must be sampled in order to estimate the true proportion to within 0.04 with 95% confidence using the large-sample method.
We need at least n stores.
n is found when M = 0.04. So
Rounding up
We need at least 243 stores.
Factor out -4
-4(x^3+3x^2-2x-6
Factor out x^2
-4(x^2(x+3)-2x-6)
Factor out -2
-4(x^2(x+3)-2(x+3))
Factor out x+3
-4(x+3)(x^2-2)
Y=mx +b plug that in , so the 23.95 would be the flat fee then you add 0.32
250 =23.95+0.32 subtract from both sides then divide the answer is 10 miles
Answer:
y = 5
Step-by-step explanation:
Expand the logarithm:
_____
You can also take the antilog first:
5y = y²
y(y -5) = 0 . . . . . subtract 5y, factor
y = 0 or 5 . . . . . y=0 is not a viable solution, so y=5.
