Answer:37.2 sec
Step-by-step explanation:
Given
Joel takes 81 sec for 14 mile long track
speed of joel
mi/min=10.37 mi/min
Jason takes 69 sec for 14 mi track
so jason speed is ![\frac{14}{1.15} mi/min=12.17 mi/min](https://tex.z-dn.net/?f=%5Cfrac%7B14%7D%7B1.15%7D%20mi%2Fmin%3D12.17%20mi%2Fmin)
if both starts from same spot in opposite direction then
![\frac{x}{10.37}=\frac{14-x}{12.17}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B10.37%7D%3D%5Cfrac%7B14-x%7D%7B12.17%7D)
where x is distance covered by Joel
then x=6.44 miles
therefore time required
![t=\frac{6.44}{10.37}=0.621 min\approx 37.2 sec](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B6.44%7D%7B10.37%7D%3D0.621%20min%5Capprox%2037.2%20sec)
Constructing What? you did not finish the question
Answer:
No, because the interval contains 0.96.
Step-by-step explanation:
edge2021
1st urn : 5 white, 8 yellow....total of 13 balls
P(white) = 5/13
2nd urn : 9 white, 2 yellow...total of 11 balls
P(white) = 9/11
P(both events happening) = 5/13 * 9/11 = 45/143 <=
If you have a calculator with statistical functions, that's the way to go.
On my TI-83, I typed in invNorm(0.88) and got the result z = 1.17.
88% of the area under the normal curve is to the left of z = 1.17.