A program that is required to three (3) numbers. calculate and print their total is given below:
<h3>The Program</h3>
import java.util.Scanner;
public class SumAndAverage {
public static void main(String[ ] args) {
System.out.println("Enter three numbers - ");
// Accepting and finding sum of numbers.
int sum = 0;
Scanner sc = new Scanner(System.in);
for (int i = 0; i < 3; i++)
sum += sc.nextInt( );
// Printing sum and average.
System.out.println("Sum - " + sum);
System.out.println("Average - " + (sum / 3f));
}
}
The output would request three different numbers, then add them up, and display the output of the sum and then display or print their total
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44–66
According to sources, the most probable answer to this query is 44–66 point size.
This is because the eyes and the illustration should match the proportion of distance and height factors.
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My recommendation as an immediate response to prevent further spoofing of the host is to Revoke the host's certificate.
<h3>What does revoke certificate mean?</h3>
Certificate revocation is the process by which one can invalidate a TLS/SSL and this is one that is often done before its scheduled expiration date.
Note that A certificate need to be revoked immediately and as such, based on the case above, My recommendation as an immediate response to prevent further spoofing of the host is to Revoke the host's certificate.
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Answer:
def newton(n):
#Define the variables.
t = 0.000001
esti = 1.0
#Calculate the square root
#using newton method.
while True:
esti = (esti + n / esti) / 2
dif = abs(n - esti ** 2)
if dif <= t:
break
#Return the result.
return esti
#Define the main function.
def main():
#Continue until user press enters.
while True:
try:
#Prompt the user for input.
n = int(input("Enter a number (Press Enter to stop):"))
#display the results.
print("newton = %0.15f" % newton(n))
except:
return
#Call the main function.
main()
Answer:
spanish
Explanation:
no ingles a me pisquen spanish soy tu amigos teacher