The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
Read more about radius
brainly.com/question/13449316
#SPJ4
A) cylinder
b) triangular pyramid
13000-5600=7400...that's about it, just multiply then subtract
Answer:
5x - 4y = 32
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
5x - 4y = 36 ( subtract 5x from both sides )
- 4y = - 5x + 36 ( divide all terms by - 4 )
y =
x - 9 ← in slope- intercept form
with slope m = 
Parallel lines have equal slopes, thus
y =
x + c ← is the partial equation
To find c substitute (8, 2) into the partial equation
2 = 10 + c ⇒ c = 2 - 10 = - 8
y =
x - 8 ← in slope- intercept form
Multiply through by 4
4y = 5x - 32 ( subtract 4y from both sides )
0 = 5x - 4y - 32 ( add 32 to both sides )
32 = 5x - 4y, that is
5x - 4y = 32 ← in standard form