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3 years ago

Using f(x)=2x-3 and g(x)=4x, what is f(2) - g(3)

1 answer:

6 0

First fine f(2).

f(2) = 2*2 - 3
f(2) = 4 - 3
f(2) = 1

Now g(3).

g(3) = 4*3
g(3) = 12

Now subtract 1 - 12 = -11

-11 is your answer.

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4/5 ÷ 2/5 = ?????????

Usimov [2.4K]

Answer:

Step-by-step explanation:

4/5 divided by 2/5 is equal to

4/5 * 5/2

thats 20/10

thats 2

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3 years ago

Why is the median preferred to the mean for skewed data

Elenna [48]

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3 years ago

Read 2 more answers

(trigonometry) solve for x

Olin [163]

Answer:

Step-by-step explanation:

take 23 degree as reference angle

using tan rule

tan 23=opposite/adjacent

0.42=25/x

x=25/0.42

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3 years ago

CHECK ALL ANSWERS THAT APPLY*

Musya8 [376]

Answer:

We get t= 7.22 and t=0.28

The correct options are Option A and Option G

Step-by-step explanation:

The height h of toy rocket at time t seconds after launch is given by the equation $h(t) = -16t^2 + 120t + 8$

We need to find how many seconds until the rocket is 40 feet?

We are given height of rocket h(t) = 40 feet

and we need to find time t

Using the equation $h(t) = -16t^2 + 120t + 8$ we can find time t

We have h(t)=40

$h(t) = -16t^2 + 120t + 8\\Put\:h(t)=40\\40= -16t^2 + 120t + 8\\16t^2-120t-8+40=0\\16t^2-120t+32=0$

Now, we will solve the quadratic equation using quadratic formula: $t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

We have a =16, b=-120 and c=32

Putting values and finding t

$t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\t=\frac{-(-120)\pm\sqrt{(-120)^2-4(16)(32)}}{2(16)}\\t=\frac{120\pm\sqrt{14400-2048}}{32}\\t=\frac{120\pm\sqrt{12352}}{32}\\t=\frac{120\pm111.12}{32}\\t=\frac{120+111.12}{32}, t=\frac{120-111.12}{32}\\t=7.22\:,\:t=0.28$