2 years ago

How do you write 2sin5cos5 as a single trigonomic ratio?

1 answer:

6 0

Answer:

ertyui

Step-by-step explanation:

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wlad13 [49]

Answer:

Step-by-step explanation:

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2 years ago

scoundrel [369]

452,165.36 ? That should be the answer lol

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2 years ago

blagie [28]

Partial products are the products obtained during the intermediate stages in order to complete a multiplication process.

Consider 68 $\times$ 43, we have to determine the partial products in this.

Now, $68 \times 43$

Expanding this, we get

$(60+8) \times (40+3)$

= $(60\times 40) +(60 \times 3) + (8 \times 40) + (8 \times 3)$

= 2400 + 180 + 320 + 24

= 2924

Hence, $8 \times 40=320$ and $8 \times 3 = 24$ are the required partial products in the product of 68 and 43.

So, Option 3 and 4 are the correct answers.

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2 years ago

Olegator [25]

The scale is 1 cm per 2 ft

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2 years ago

Elan Coil [88]

Answer:

Madison is gonna need to buy 250 pounds of meat.

Feel free to Brainliest :)

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3 years ago