2 years ago

How do you write 2sin5cos5 as a single trigonomic ratio?

Mathematics

1 answer:

erastova [34]2 years ago

6 0

Answer:

ertyui

Step-by-step explanation:

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For which inequality would x = 8 not be a solution?

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Put the value of x to the inequality:

$4x+3 > 0\\L=4(8)+3=32+3=35;\qquad R=0;\qquad L > R\ CORRECT\\\\9x-5 < 100\\L=5(8)-5=40-5=35;\qquad R=100;\qquad 35 < 100\ CORRECT\\\\x+4\leq10\\L=8+4=12;\qquad R=10;\qquad 12 > 10\ INCORECT (\leq)\\\\72\div x\geq4\\L=72\div 8=9;\qquad R=4;\qquad 9\geq4\ CORRECT$