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4 years ago

What is this in simplest form?

Mathematics

2 answers:

const2013 [10]4 years ago

7 0

The answer to this problem is -14a^5c^9

alexira [117]4 years ago

6 0

Simplest form is when you turn a number in half until it’s the least value as you can get. For example 10 it’s simplest form is 5. And 2 it’s simplest form is 1

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Jessica and Nancy are members of different video game libraries. Jessica pays a membership fee of $40, and she pays $5 for every

ad-work [718]

Jessica pays a membership fee of $40 so that's given to us Jessica has a membership fee of $40 (given)
Nancy has a membership fee of $30 (y intercept of the equation)
so how much is jessica going to pay is $10 more than Nancy

4 0

3 years ago

Read 2 more answers

NEED HELP PLEASE I BEG OF YOU

SVEN [57.7K]

Answer:

should be 40, because the top line is 40 and the line on the side is the same length

Step-by-step explanation:

5 0

3 years ago

Diego said that the awnser to the question "How many groups of 5/6 are in 1?" Is 6/5 or 1 1/5.Do you agree with his statement? E

slamgirl [31]

Answer:

Diego is correct.

He has correctly divided 1 in groups of $\frac{5}{6}$ .

Step-by-step explanation:

The question 'How many groups of 5/6 are in 1?' means that we need to divided 1 into groups of $\\frac{5}{6}$ .

When we form groups from a given total, we divided the total by the size of the group.

If we are dividing $N$ number of people in groups of $x$ number of people, then the expression to find the number of groups formed can be given as:

⇒ $\frac{N}{x}$

For this question the data given is:

$N=1$

$x=\frac{5}{6}$

So, the number of groups formed can be given as:

⇒ $\frac{1}{\frac{5}{6}}$

When divisor is a fraction, then we multiply the reciprocal of the divisor with the dividend.

⇒ $1\times\frac{6}{5}$

⇒ $\frac{6}{5}$

In order to convert fraction to mixed number we will divide numerator with denominator and then write the quotient as whole number, remainder as numerator and the denominator remains as it is.

On dividing 6 by 5, the quotient =1 and remainder =1. Thus the mized number is:

⇒ $1\frac{1}{5}$

Thus, there are $\frac{6}{5}$ or $1\frac{1}{5}$ groups in 1. This matches with Diego's answer and hence he is correct.

3 0

3 years ago

Suppose that prior to conducting a coin-flipping experiment, we suspect that the coin is fair. How many times would we have to f

BabaBlast [244]

Answer:

153 times

Step-by-step explanation:

We have to flip the coin in order to obtain a 95.8% confidence interval of width of at most .14

Width = 0.14

ME = $\frac{width}{2}$

ME = $\frac{0.14}{2}$

ME = $0.07$

$ME\geq z \times \sqrt{\frac{\widecap{p}(1-\widecap{p})}{n}}$

use p = 0.5

z at 95.8% is 1.727(using calculator)

$0.07 \geq 1.727 \times \sqrt{\frac{0.5(1-0.5)}{n}}$

$\frac{0.07}{1.727}\geq sqrt{\frac{0.5(1-0.5)}{n}}$

$(\frac{0.07}{1.727})^2 \geq \frac{0.5(1-0.5)}{n}$

$n \geq \frac{0.5(1-0.5)}{(\frac{0.07}{1.727})^2}$

$n \geq 152.169$

So, Option B is true

Hence we have to flip 153 times the coin in order to obtain a 95.8% confidence interval of width of at most .14 for the probability of flipping a head

6 0

3 years ago

40 POINTS !! 40 POINTS !! PLEASE HELP , DONT SKIP ! NO LINKS OR FILES.

Tanzania [10]

4 x’s for 1/4
2 x’s for 2/4
1 x for 3/4
2 x’s for 1

5 0

3 years ago

Read 2 more answers