Answer:
V=9
Step-by-step explanation:
9 times 3 equals 27 and that's how I got 9
Answer:
Step-by-step explanation:
Count pairs (a, b) whose sum of squares is N (a^2 + b^2 = N)
Given a number N, the task is to count all ‘a’ and ‘b’ that satisfy the condition a^2 + b^2 = N.
Note:- (a, b) and (b, a) are to be considered as two different pairs and (a, a) is also valid and to be considered only one time.
Examples:
Input: N = 10
Output: 2
1^2 + 3^2 = 9
3^2 + 1^2 = 9
Input: N = 8
Output: 1
2^2 + 2^2 = 8
Answer:
They do not form a Pythagorean Triple.
If it was a Triple, 4^2+5^2 should equal 6^2.
4^2+5^2=16+25=41
6^2=36
41≠26
It doesn't work, therefore it is not a Pythagorean Triple.
Answer:
Step-by-step explanation:
<, > - open circle
≤, ≥ - closed circle
<, ≤ - draw the line to the left
>, ≥ - draw the line to the right
