Answer:
x² + 2x + (3 / (x − 1))
Step-by-step explanation:
Start by setting up the division:
.........____________
x − 1 | x³ + x² − 2x + 3
Start with the first term, x³. Divided by x, that's x². So:
.........____x²______
x − 1 | x³ + x² − 2x + 3
Multiply x − 1 by x², subtract the result, and drop down the next term:
.........____x²______
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
Repeat the process over again. First term is 2x². Divided by x is 2x. So:
.........____x² + 2x __
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
Multiply, subtract the result, and drop down the next term:
.........____x² + 2x __
x − 1 | x³ + x² − 2x + 3
.........-(x³ − x²)
...........----------
...................2x² − 2x
.................-(2x² − 2x)
.................---------------
.....................................3
x doesn't divide into 3, so that's the remainder.
Therefore, the answer is:
x² + 2x + (3 / (x − 1))
<span>Find
the values of a and b that make f continuous everywhere. f(x) = x^2 − 4
/ x − 2 if x < 2 ax^2 − bx + 3 if 2 ≤ x < 3 4x − a + b if x ≥ 3
</span>
a=7/12
b=13/2
Answer:
6+2+3+3+3+5=22 is a correct answer