Solve each system of equations by using elimination.

Rama09 [41]

First we need to find the gradient of K
which is y1-y2/x1-x2
(-1,3) and (5,-2)
so it becomes 3-(-2)/-1-5
m=-5/6
when two lines are perpendicular their gradients multiply to make -1
that means the gradient of L has to be 6/5
we can substitute the point on L (5,-2) and the gradient of 6/5 into y=mx+c
-2 = (6/5) x 5 + c
c = -8
the equation of line L is y= 6x/5 -8

6 0

2 years ago

Read 2 more answers

The rays OM , ON , and OP in the figure, coincide at time t=0. At the same instant of time OM and OP rotate in the plane about p

dangina [55]

Note:

Note that the shape is a circle(s), as they all will rotate until they coincide. However, they are rotating towards each other

Step-by-step explanation:

One is rotating at 3°, while the other is rotating at 6°. We do not need to both with ON, for the question is not asking for that segment.

A circle has 360° To solve this, we must know that "the other" must complete a circle and overtake the other one.

So. First, solve for the circle (360°)

360/6 = 60

It takes one of the rays to rotate a full circle 60 seconds.

The other, at the same time, has rotated half way, as:

360/3 = 120

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Remember that one of the rays (the one that is faster), completes it's turn twice as fast. This means that you must solve for the mean:

(60 + 120)/2 = 180/2 = 90

90 seconds will be used until one overtakes the other

~<em>Senpai</em>

6 0

3 years ago

Giraffes are herbivores,or plant eaters. A giraffe can eat up to 75 pounds of leaves each day. Write and evaluate an expression

Rudik [331]

Answer: 2625

Let’s say you multiply 5 giraffes by 75 pounds = 375lbs 5 giraffes eat a day multiply the 5 giraffes and they answer should be 2625lbs

7 0

3 years ago

Historically 80% of the monitors made by your company will pass your stringent quality control checks. 40 monitors have just com

madam [21]

Answer:

a) 10.75% probability that exactly 30 of them will pass the quality control checks.

b) Expected value is 32

Variance is 6.4

Step-by-step explanation:

For each monitor, there are only two possible outcomes. Either they will pass the quality checks, or they will not pass these checks. The probability of a monitor passing these checks is independent of other monitors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$