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Archy [21]
3 years ago
5

Solve each system of equations by using elimination.

Mathematics
1 answer:
Wewaii [24]3 years ago
5 0
What grade are you in
You might be interested in
An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ = 42 and σ = 5.5.
alexandr1967 [171]

Answer:

a)P( X

We want this probability:

P( X >64)

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X >64) =P(Z> \frac{64-42}{5.5}) =P(Z>4)=0.0000316

b) For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.25   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.674. On this case P(Z<0.674)=0.75 and P(z>0.674)=0.25

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.674

And if we solve for a we got

a=42 +0.674*5.5=45.707

So the value of height that separates the bottom 75% of data from the top 25% is 45.707.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(42,25.5)  

Where \mu=42 and \sigma=5.5

And we want this probability:

P( X

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X

We want this probability:

P( X >64)

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X >64) =P(Z> \frac{64-42}{5.5}) =P(Z>4)=0.0000316

Part b

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.25   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.674. On this case P(Z<0.674)=0.75 and P(z>0.674)=0.25

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.674

And if we solve for a we got

a=42 +0.674*5.5=45.707

So the value of height that separates the bottom 75% of data from the top 25% is 45.707.  

8 0
3 years ago
What is 2/5-3/10 equal to
Ilia_Sergeevich [38]

Answer:

1/10

Step-by-step explanation:

2/5=4/10

4/10-3/10=1/10

7 0
3 years ago
What is the price per kilogram of candy if you paid $2.25 for 1 1/4 kg?
Nostrana [21]

Answer:

1.80 dollars per kilogram of candy.  

Step-by-step explanation:

How to get this is simple and you will use it later in life, you take the price of the candy you paid for, then you divide it by the amount in pounds, or kilograms, to get the price per pound.  


2.25 / 1.25 = 1.80


Cheers!

8 0
3 years ago
Read 2 more answers
If y=2x- 3, find the value of y when x=2
Ira Lisetskai [31]

y = 2x - 3

y = 2 * 2 - 3

y = 4 - 3

y = 1

3 0
3 years ago
Select the correct answer from each drop-down menu.
il63 [147K]

Answer:

Find below correct question:

When she was 20, liz started saving $6,000 a year for retirement. her goal is to reach & 100,00 in savings by the time she’s 30. her account earns 8% interest per year, compounded annually. liz (will/ won’t) have saved $100,000 by age 30. she’ll (exceed/ fall short of) her goal by about ($10,081/ $13,081/ $14,011)

liz won’t have saved $100,000 by age 30. she’ll fall short of her goal by about  $13,081

Step-by-step explanation:

First and foremost we need to know the worth of Liz's retirement savings when she is 30 using excel fv formula as follows:

=fv(rate,nper,-pmt,pv)

rate is the interest earned per year which is 8%

nper is the duration of savings which is 10 years

pmt is the amount of yearly savings which is $6,000

pv is the present worth of total savings which is not known

=fv(8%,10,-6000,0)=$86,919.37  

Hence,Liz would be not be able to reach $100,000 at age 30.

Shortfall=$100,000-$86,919.37  =$ 13,080.63  

5 0
4 years ago
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