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yanalaym [24]
3 years ago
7

Solve x^3 - 3x^2 - 13x + 15= x^4 + 3x^3 - 8x^2 + 5x - 25= x^3 - 2x^2 - x + 2 =

Mathematics
1 answer:
AleksAgata [21]3 years ago
5 0
We have Been doing Solving qart log
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Help timed test! At which root does the graph...
Anastaziya [24]

Answer:

x = -2

Step-by-step explanation:

The way you can tell if the graph is going to cross the x-axis or just touch the x-axis is by looking at the power of the factor.

(x - 5)^3 has a power of 3 which is an ODD number. An ODD power means that the graph will cross through the x-axis.

(x + 2)^2 has a power of 2 which is an EVEN number. An EVEN power means that the graph will touch the x-axis.

To find where it will touch the axis set the factor equal to zero and solve.

(x + 2) = 0

subtract 2 from both sides

x = -2

5 0
3 years ago
How to find b with (4a-b) + (4b-a) = 180
Sunny_sXe [5.5K]

Answer:

just simplify it ...

Step-by-step explanation:

  1. 4a-b+4b-a=180
  2. 3a+3b=180
  3. 3(a+b)=180
  4. both sides divide by 3
  5. a+b =60
  6. b=60-a
6 0
3 years ago
11 POINTS PLZ HELP EMERGENCY
Bad White [126]

Part A

The given expression is:

(-5(1+2i)+3i(3-4i)

We expand to get:

-5-10i+9i-12i^2

Note that i^2=-1

12-5-10i+9i

-5-10i+9i+12

7-i

Part Bi)

The given expression is;

\sqrt{-50}

We simplify to get:

\sqrt{25\times 2\times -1}

\sqrt{25\times} \sqr{2}\times \sqrt{-1}

Note that:

\sqrt{-1}=i

5\sqr{2}i

This is now of the form a+bi, where a=0,b=5\sqr{2}.

This explains why it is a complex number;

Part bii)

The given expression is :

\frac{\sqrt{-50} }{\sqrt{5}}

We simplify to get

\sqrt{\frac{-50 }{5}}

\sqrt{-25}

\sqrt{-25}=\sqrt{25}\times \sqrt{-1}

\sqrt{-25}=5\times i

\sqrt{-25}=5i

Part C

We want to simplify:

i^{22}

We rewrite in terms of i^2

i^{22}=(i^2)^{11}

i^{22}=(-1)^{11}

i^{22}=-11

5 0
3 years ago
Helppp need to find x and r TRIG!​
jolli1 [7]

Answer:

x = 18

18√2

Step-by-step explanation:

This is a special right triangle with angle measures 45° 45° 90°

in this special triangle the side lengths are expressed as a, a, and a√2

So x = a and x = 18

r = a√2 and r = 18√2

7 0
3 years ago
write and solve the differential equation that models the following statment. "the rate if change of W with respect to x is prop
Vaselesa [24]

Answer:

\int k(x + 18)dx = \int kx + 18k dx = k\frac{x^{2} }{2} + 18kx + C where C is the constant of integration.

Step-by-step explanation:

i)it is given that the rate of change of W with respect to x is proportional to          

     x + 18. Therefore \frac{dW}{dx} = k(x + 18) where k is a constant.

ii) Therefore \int k(x + 18)dx = \int kx + 18k dx = k\frac{x^{2} }{2} + 18kx + C where C is the constant of integration.

iii) the complete solution can only be found if we know the constant of proportion and also the constant of integration.

4 0
3 years ago
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