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zepelin [54]
3 years ago
6

Equilateral triangles are triangles . ​

Mathematics
2 answers:
Alexandra [31]3 years ago
4 0

Answer:

That is correct

Step-by-step explanation:

Schach [20]3 years ago
4 0

Answer:

ohmygosh

Step-by-step explanation:

I didn't know that...wow big brains

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The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each
Fynjy0 [20]

Answer:

\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

Step-by-step explanation:

Given equation of ellipsoids,

u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}

The vector normal to the given equation of ellipsoid will be given by

\vec{n}\ =\textrm{gradient of u}

            =\bigtriangledown u

           

=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})

           

=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}

           

=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}

Hence, the unit normal vector can be given by,

\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}

             =\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}

             

=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

Hence, the unit vector normal to each point of the given ellipsoid surface is

\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

3 0
3 years ago
The San Andreas fault separates the pacific plates from the North America plate. The pacific plate moved northward relative to t
lesantik [10]

Answer:

The time, t it will take LA and San Francisco to be next to each other is 8,245,614.04 years which is over 8 million years

Step-by-step explanation:

The given parameters are;

The speed with which the pacific plate moved northward relative to the North American plate = 5.7 cm/year = 5.7 × 10⁻⁵ km/year

The distance between current LA and San Francisco = 470 km

From the formula for speed, s, we have

Speed = Distance/Time

Therefore, Time, t = Distance/Speed

The time, t it will take LA and San Francisco to be next to each other is given as follows;

t = (Distance between LA and San Francisco)/(The speed with which the pacific plate)

t = (470 km)/(5.7 cm/year) = 470/(5.7 × 10⁽⁻⁵⁾) = 8245614.04 years

Therefore, the time, t it will take LA and San Francisco to be next to each other is 8245614.04 years.

6 0
3 years ago
I don't get this. can someone help me. I have a whole packet of this.
Harrizon [31]
For #2, ∠3 and ∠1 are supplementary. You know that the measure of ∠1 is 162°, so what is ∠3? 180-162=18.
m∠3=18° if ∠1=162°.
Hope this helped!
7 0
3 years ago
For each data set, find the mean, the first and third quartiles, and the interquartiles. Texts per day: 24, 53, 38, 12, 31, 19,
kolezko [41]
Mean = 29
Q1 = 19
Q2 = 26
Q3 = 38
IQR = Q3 - Q1 = 38 - 19 = 19
8 0
2 years ago
Find the number of terms and the degree of this polynomial. -9
Korvikt [17]

Answers:

  • Number of terms: 1
  • Degree:  9

===============================================

Explanation:

This is consider a monomial since we only have one term. Terms are separated by a plus sign, so something like 5x^2+10x has two terms.

The degree of a polynomial is the largest exponent when dealing with single variables. In the case of 9r^9, the largest exponent is 9, so the degree is 9. Going back to an example like 5x^2+10x, the largest exponent is 2 so this is the degree of this example.

8 0
3 years ago
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