Question

A bird is flying at an elevation of 3 5/8 feet above sea level. A fish swims directly under the bird at a depth of 5 1/3 feet below sea level. How far apart are the two creatures?

Answer 1

Given :

Distance of bird from sea level, $d_1 = 3\dfrac{5}{8} = \dfrac{29}{8}\ feet$ .

Distance between fish and sea level, $d_2=5\dfrac{1}{3}=\dfrac{16}{3}\ feet$ .

To Find :

Distance between bird and fish.

Solution :

Distance between bird and fish is given by :

$D=d_1+d_2\\\\D = \dfrac{29}{8}+\dfrac{16}{3}\\\\D=8.958\ feet$

Therefore, distance between bird and fish is 8.958 feet.

Hence, this is the required solution.