Given a polyhedron with 15 faces and 32 edges, how many vertices does it have
1 answer:
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Solve for
y
y in
2
x
+
y
=
8
2x+y=8.
y
=
8
−
2
x
y=8−2x
2 Substitute
y
=
8
−
2
x
y=8−2x into
4
x
+
6
y
=
24
4x+6y=24.
−
8
x
+
48
=
24
−8x+48=24
3 Solve for
x
x in
−
8
x
+
48
=
24
−8x+48=24.
x
=
3
x=3
4 Substitute
x
=
3
x=3 into
y
=
8
−
2
x
y=8−2x.
y
=
2
y=2
5 Therefore,
x
=
3
y
=
2
x=3
y=2
look in comments to read it better but x=3 y=2 hope this helps :)
y
y in
2
x
+
y
=
8
2x+y=8.
y
=
8
−
2
x
y=8−2x
2 Substitute
y
=
8
−
2
x
y=8−2x into
4
x
+
6
y
=
24
4x+6y=24.
−
8
x
+
48
=
24
−8x+48=24
3 Solve for
x
x in
−
8
x
+
48
=
24
−8x+48=24.
x
=
3
x=3
4 Substitute
x
=
3
x=3 into
y
=
8
−
2
x
y=8−2x.
y
=
2
y=2
5 Therefore,
x
=
3
y
=
2
x=3
y=2
look in comments to read it better but x=3 y=2 hope this helps :)