How many solutions does the following system of equations have? y=5/2x+2 2y= 5x +4
1 answer:
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Answer:
The positive numbers are 51 and 53
Step-by-step explanation:
Let first odd integer be x and another odd integer is (x+2).
According to the given condition,
The product of two positive consecutive odd integers is 2703 i.e.
x(x+2) = 2703
It is a quadratic equation. It can be solved as follows :
x = 51 and x = -53
Neglecting negative sign,
The first number = 51
Another number =(51+2) = 53
Hence, the positive numbers are 51 and 53.
The equation for this would be: 
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