Using the equation of the test statistic, it is found that with an increased sample size, the test statistic would decrease and the p-value would increase.
<h3>How to find the p-value of a test?</h3>
It depends on the test statistic z, as follows.
- For a left-tailed test, it is the area under the normal curve to the left of z, which is the <u>p-value of z</u>.
- For a right-tailed test, it is the area under the normal curve to the right of z, which is <u>1 subtracted by the p-value of z</u>.
- For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is <u>2 multiplied by 1 subtracted by the p-value of z</u>.
In all cases, a higher test statistic leads to a lower p-value, and vice-versa.
<h3>What is the equation for the test statistic?</h3>
The equation is given by:

The parameters are:
is the sample mean.
is the tested value.
- s is the standard deviation.
From this, it is taken that if the sample size was increased with all other parameters remaining the same, the test statistic would decrease, and the p-value would increase.
You can learn more about p-values at brainly.com/question/26454209
Answer:0.542=0.500 + 0.040+0.002
= \frac{5}{10} + \frac{4}{100} +\frac{2}{1000}
=5 tenth + 4 hundredths + two thousandths
One tenth = \frac{1}{10}
One Hundredth= \frac{1}{100}
One thousandth= \frac{1}{1000}
Step-by-step explanation:
Answer:
32a
Step-by-step explanation:
20a + 12 = 32a
Hope this helps..
(5/6 + 2/3) - (3/4 + 1/12
= 9/6 - 10/12
= 18/12 - 10/12
= 8/12
= SIMPLIFY: 2/3
Hope this helps!!