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Arturiano [62]
3 years ago
11

How many grams in a pound

Mathematics
2 answers:
lbvjy [14]3 years ago
5 0

There are 453.5 grams in 1 pound


I hope that's help and have a great night !

FinnZ [79.3K]3 years ago
5 0
For one pound there would be 453.592. Hope this helps
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Number 15. Find the equation of the line that passes through (3,-1) and is perpendicular to the line that passes through (-5, 2)
MArishka [77]
For lines to be perpendicular their slopes must be negative reciprocals of one another, mathematically:

m1*m2=-1

So we first need to find the slope of the reference line.

m=(y2-y1)/(x2-x1)=(7-2)/(-1--5)=5/4

So the perpendicular line will have a slope of:

5m/4=-1

m=-4/5

So our perpendicular line so far is:

y=-4x/5+b, now we can use point (3,-1) to solve for the y-intercept, "b"

-1=-4(3)/5+b

-1=-12/5+b

-5/5+12/5=b

7/5=b

So the line is:

y=-4x/5+7/5 or more neatly

y=(-4x+7)/5

y=-0.8x+1.4
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3 years ago
What is the order of this matrix?
myrzilka [38]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
BRAINLIEST FOR ANSWER WITH EXPLANATION<br> JUST ONE QUESTION ATTACHED BELOW:
skelet666 [1.2K]

Answer:

m=16

Step-by-step explanation:

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3 0
3 years ago
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I already solved this problem. I just need help with the HINT part.
frutty [35]
x+y=25 \\ y=25-x~~Other~number~in~terms~of~x \\ \\ x^2+y^2=313 \\ x^2+2xy+y^2=313+2xy \\ (x+y)^2=313+2x(25-x) \\ \frac{25^2-313}{2} =25x-x^2 \\ x^2-25x+156 \\ \\ \Delta =(-25)^2-4\times 1\times 156 \\ \Delta =625-624 \\ \sqrt{\Delta}=1 \\ \\ x= \frac{25 \pm 1}{2} \\ x= \left \{ {{x_1=13} \atop {x_2=12}} \right.

     The number "x" is given by:
y= \left \{ {{y_1=25-13 \rightarrow~y_1=12} \atop {y_1=25-12 \rightarrow ~y_1=13}} \right.
  
     Therefore, we have:

\boxed {S=({12,13})} \rightarrow~The~curly~braces~does~not~want~appear~here.
8 0
3 years ago
Please help with this
nataly862011 [7]

Answer:

AAS

Step-by-step explanation:

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3 years ago
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