You find the area of a triangle by using 1/2*b*h where b is the base and h is the height. since we already know the area is 20 and the height is for you plus them in so the problem would be 20= 1/2 (b) (4) then you multiply what you know together to get 20= 2b and then isolate the b by dividing both sides by two so the base should be 10 m
It could've been a PENTAGON and a SQUARE.
It could've been a HEXAGON and a TRIANGLE.
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Answer:</h2>
The ratio of the area of region R to the area of region S is:

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Step-by-step explanation:</h2>
The sides of R are in the ratio : 2:3
Let the length of R be: 2x
and the width of R be: 3x
i.e. The perimeter of R is given by:

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:
)
Hence, we get:

i.e.

Also, let " s " denote the side of the square region.
We know that the perimeter of a square with side " s " is given by:

Now, it is given that:
The perimeters of square region S and rectangular region R are equal.
i.e.

Now, we know that the area of a square is given by:

and

Hence, we get:

and

i.e.

Hence,
Ratio of the area of region R to the area of region S is:

126
explanation: solved it
Find their gradients using the change in y coords divided by the change in x coords. once you have the gradients (or slopes), multiply them by eachother - if the product is (-1) then theyre perpdendicular, if not, they are either parallel or intersect at a point