<em>Greetings from Brasil...</em>
The average for a set of 9 elements will be
(A + B + C + D + E + F + G + H + I) ÷ 9 = 20
Let's make (A + B + C + D + E + F + G + H + I) like S
<em>(I chose S to remember a sum)</em>
Let us think.....
S ÷ 9 = 20
S = 20 × 9
S = 180
So, (A + B + C + D + E + F + G + H + I) = 180
According to the statement, we will include a number (element J) in the sum to obtain a mean of (20 - 4), that is:
<h3>(A + B + C + D + E + F + G + H + I +
J) ÷ 10 = (20 - 4)</h3>
as seen above, (A + B + C + D + E + F + G + H + I) = 180, then
(180 + J) ÷ 10 = 16
(180 + J) = 160
J = 160 - 180
<h2>J = - 20</h2><h2 />
So, including the number - 20 <em>(minus 20)</em> in the original mean we will obtain a new mean whose result will be 16
Answer:
A on edge
Step-by-step explanation:
Subtract 15 from both sides
You want to focus on isolating the variable (x)
Answer:
x > 5
Step-by-step explanation:
Given that:
= -2(3x + 2) > -8x + 6
(negative sign before bracket will alter the internal signs when multiplied by each term)
= -6x - 4 > -8x +6
Taking x terms on left side and other constants on right side
= -6x + 8x > 6 +4
Signs will be changer for transferred terms
= 2x > 10
By Dividing both sides 2 we get
=x > 10/2
= x >5
Let be y =f(x)= x3, f(-x) = (-x)^3 = - x^3 = - f(-x), f(-x) = (-x)^3, f(-x) = - f(<span>-x)
the equation is odd</span>
