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Leona [35]
3 years ago
9

Help! Factor the expressions. x^2 − 4x − 45 =

Mathematics
1 answer:
nasty-shy [4]3 years ago
8 0

Answer:

(x - 9)(x + 5)

Step-by-step explanation:

x² − 4x − 45 =

= x² + 5x  - 9x - 45

= x(x + 5) - 9(x + 5)

= (x - 9)(x + 5)

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(x - 2)(x² + 2x + 4) = 0​
Ber [7]

We have to find the value of x from the given equation.

  • (x - 2)(x² - 2x + 2) = 0 is a quadratic equation, so it will have two values.

Step: Write the equation in simplest form.

  • (x - 2)(x² - 2x + 1) = 0

Step: Solve the problem by spiltting method.

  • (x-2)(x² - x -x + 1) = 0
  • (x - 2)(x²-x - x + 1) = 0
  • (x - 2) [x(x - 1) -1(x -1)]
  • (x - 2)[(x-1)(x-1)]

Step: Solve the problem with using algebraic formula.

{x-1](x-1)

Step : We have used a²-b² to solve the problem.

(x-2)(x² - x -x + 1) = 0

(x - 2)(x²-x - x + 1) = 0

(x - 2) [x(x - 1) -1(x -1)]

(x - 2)[(x-1)(x-1)]

Therefore, the possible factorization is (x - 2)[(x-1)(x-1)].

4 0
3 years ago
Solve the following sysyem of equations by the substitution method.  5x+y=8<br> 3×+y=8
meriva
5x+y=8\\&#10;3x+y=8\\\\&#10;y=-5x+8\\&#10;3x+y=8\\\\&#10;3x-5x+8=8\\&#10;-2x=0\\&#10;x=0\\\\&#10;y=-5\cdot0+8\\&#10;y=8\\\\&#10;\boxed{(x,y)=(0,8)}
6 0
3 years ago
Convert 9 over 16 to a decimal.<br> A. 0.4225<br> B. 0.5225<br> C. 0.5625 <br> D. 0.7455
Brums [2.3K]
C. 0.5625...you find the answer by dividing 6 by 19 :)
7 0
3 years ago
Read 2 more answers
PLEASE HELP NEED TO KNOW ASAP
ira [324]
6. three kids and four adults
3 0
3 years ago
Pleases someone explain
Nikolay [14]

When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

\frac{1}{y^{-2}} =\frac{y^2}{1} or y^2

2x^{-3} or \frac{2^1x^{-3}}{1} =\frac{2}{x^3}

\frac{1}{x^{-5}} =x^5

When a base with an exponent is divided by a base with an exponent, you subtract the exponents together. (But you can only combine the exponents when the bases are the same)

For example:

\frac{x^2}{y}   (can't combine because they have different bases of y and x)

\frac{x^5}{x^3} =x^{(5-3)}=x^2

\frac{2^2}{2} =2^{(2-1)}=2^1 = 2

When you multiply an exponent directly to a base with an exponent, you multiply the exponents together.

For example:

(x^2)^3=x^{(2*3)}=x^6

(y^2)^{10}=y^{(2*10)}=y^{20}

\frac{2e^0}{(e^{-3})^2}     First multiply the exponents together in the denominator

\frac{2e^0}{e^{(-3*2)}}= \frac{2e^0}{e^{-6}}        Now subtract the exponents together

2e^{(0-(-6))}  (two negative signs cancel each other out and become positive)

2e^{(0+6)}

2e^6

7 0
3 years ago
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