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Leona [35]
3 years ago
9

Help! Factor the expressions. x^2 − 4x − 45 =

Mathematics
1 answer:
nasty-shy [4]3 years ago
8 0

Answer:

(x - 9)(x + 5)

Step-by-step explanation:

x² − 4x − 45 =

= x² + 5x  - 9x - 45

= x(x + 5) - 9(x + 5)

= (x - 9)(x + 5)

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U can just find the slope. From B to A it is up 8 and 3 to the right. So 8/3 which is 2.6 rounded. The answer is C
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Please help as soon as possible.. I don’t understand this.
damaskus [11]

Answer:

45ft squared

Step-by-step explanation:

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3 0
3 years ago
An automatic filling machine is used to fill bottles with liquid detergent. A random sample of 18 bottles results in a sample st
Nookie1986 [14]

Answer:

\frac{(17)(0.038)^2}{32.64} \leq \sigma^2 \leq \frac{(17)(0.038)^2}{6.66}

0.0008 \leq \sigma^2 \leq 0.0037

Step-by-step explanation:

Data given and notation

s=0.038 represent the sample standard deviation

\bar x represent the sample mean

n=18 the sample size

Confidence=97.5% or 0.975

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=18-1=17

Since the Confidence is 0.975 or 97.5%, the value of \alpha=0.025 and \alpha/2 =0.0125, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.0125,17)" "=CHISQ.INV(0.9875,17)". so for this case the critical values are:

\chi^2_{\alpha/2}=32.64

\chi^2_{1- \alpha/2}=6.66

And replacing into the formula for the interval we got:

\frac{(17)(0.038)^2}{32.64} \leq \sigma^2 \leq \frac{(17)(0.038)^2}{6.66}

0.0008 \leq \sigma^2 \leq 0.0037

3 0
3 years ago
Which equation correctly applies the distributive property?
KonstantinChe [14]
A is the correct answer
4 0
3 years ago
Round 3817453 to the nearest 100
AlladinOne [14]
3817500 is your answer
7 0
3 years ago
Read 2 more answers
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