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3 years ago

What is the sum of x2-3x+7 and 3x2+5x-9

Mathematics

1 answer:

Ghella [55]3 years ago

5 0

(x² - 3x + 7) + (3x² + 5x - 9)
(x² + 3x²) + (-3x + 5x) + (7 - 9)
4x² + 2x - 2

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Which function is a quadratic function? u(x) = –x 3x2 – 8 v(x) = 2x2 8x3 9x y(x) = x2 3x5 4 z(x) = 7x2 2x3 – 3.

Komok [63]

The function $u(x)=-x+3x^{2} -8$ is a quadratic function due to the highest exponent being 2.

Given functions are:

$u(x)=-x+3x^{2} -8$

$v(x)=2x^{2} +8x^3+9x$

$y(x)=x^{2} +3x^5+4$

$z(x) =7x^{2} +2x^3-3$

<h3>What is a quadratic function?</h3>

A function of the form $f(x)=ax^{2} +bx+c$ with $a\neq 0$ is called a quadratic function means the highest exponent of polynomial should be 2.

Let us check one by one.

$u(x)=-x+3x^{2} -8$

Highest exponent =2

The function is also of form $f(x)=ax^{2} +bx+c$ so u(x) is a quadratic function.

The functions v(x), y(x), and z(x) are having highest exponents as 3,5, and 3 respectively so they are not quadratic functions.

Hence, the function $u(x)=-x+3x^{2} -8$ is a quadratic function due to the highest exponent being 2.

To get more about quadratic functions visit:

brainly.com/question/1214333

7 0

1 year ago

Simplify (4^7/5^2)^3

Nuetrik [128]

Answer:

4²¹/5⁶ or 4398046511104/15625

Step-by-step explanation:

Remember, when raising a term with an exponent to some power, you must multiply the powers.

$(\frac{4^{7} }{5^{2} })^{3} \\\\ = (\frac{(4^{7})^{3} }{(5^{2})^{3} }) \\\\= \frac{4^{7 * 3} }{5^{2* 3} } \\\\= \frac{4^{21} }{5^{6} } \\\\=\frac{4398046511104}{15625}$

5 0

2 years ago

Read 2 more answers

Help.........................<br><br>

garri49 [273]

<h3>Answer: Choice A</h3>

$x^2\left(\sqrt[4]{x^2}\right)$

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

$\sqrt[4]{x} = x^{1/4}$

The same applies to x^10 as well

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}$

Multiply the exponents 10 and 1/4 to get 10/4

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}$

$\sqrt[4]{x^{10}} = x^{10/4}$

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

$x^{m/n} = x^a\sqrt[n]{x^b}$

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

$x^{m/n} = x^a\sqrt[n]{x^b}$

turns into

$x^{10/4} = x^2\sqrt[4]{x^2}$

which means

$\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}$

7 0

2 years ago

Find an ordered pair , x y that is a solution to the equation. 3x-y=1

NemiM [27]

Answer:

2,5

Step-by-step explanation:

2,5 is just one of the many solutions to this problem. you can just take a random number for x, for example 2. your equation will look like this 3(2)-y=1. now you just solve for y. 3x2=6. 6-1=5. so y=5.

3 0

2 years ago

Pls help I will give Brainlyest

baherus [9]

Answer:

FALSE

Step-by-step explanation:

If p could equal 10, 20, 30 or 40 lets put each of them in the expression 7.4p<=74

1. 7.4 times 10 equals 74 so that work✅

2. 7.4 times 20 equals 148 so that does not work X

3. 7.4 times 30 equals 222 so that does not work X

4. 7.4 times 40 equals 296 so that does not work X

8 0

2 years ago