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alex41 [277]
3 years ago
10

How do you solve for x using the problem above?

Mathematics
2 answers:
spin [16.1K]3 years ago
6 0
First you have to subtract 35 on both sides, then you would have to divide by 90
Grace [21]3 years ago
5 0
Step 1: <span>Find the Greatest Common Factor (GCF)
1. What is the largest number that divides evenly into </span>90x and 35&#10;? 5

2. What is the highest degree of x that divides evenly into 90x and 35? None, x is not in every term

3. Multiplying the results above, the GCF is 5

(The GCF is 5)

Step 2: Factor out the GCF 
1. <span>Put the GCF as the first term
2.</span><span>Then, in parentheses, divide each term by the GCF

</span>5( \frac{90x}{5} + \frac{35}{5})
<span>
Step 3: </span><span>Simplify each term in parentheses

</span>5(18x+7)
<span>
Done! :)</span>
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Divide the 240g into the ratio 5:3:4?​
Leona [35]

5x+ 3x +4x =12x

12x =240

X=20

100:60:80

5 0
3 years ago
Use the numbers 1-12 one time each to creat four true statements with addition, multiplication, subtraction and division
laila [671]

If you mean that you can only use each number along the four expressions, it looks impossible to me. Here's the proof.

Multiplications and divisions are the most restrictive operations, because only some triplets will work. In particular, you can choose

(2,3,6),\ (2,4,8),\ (2,5,10),\ (2,6,12),\ (3,4,12)

I'm listing them in triplets because you can use them in many ways. For example, the first triple can be used to generate

2\cdot 3 = 6,\quad 3\cdot 2 = 6,\quad 6\div 3 = 2,\quad 6\div 2 = 3

But it doesn't really matter, in all cases you used numbers 2,3, and 6.

If you look closely, all triplets but the last one involve 2. This means that we must use the last one, because otherwise we would use two triplets with two, and we would have repetitions.

So, we surely have to use (3,4,12), either to write 3\cdot 4=12 or 12\div 4=3.

This means that we can't use 3, 4 and 12 anymore. The only triplet remaining is (2,5,10).

For example, let's say that our multiplication is 2\cdot 5 = 10 and our division is 12\div 4 = 3.

We're left with the following numbers:

1,\ 6,\ 7,\ 8,\ 9,\ 11

From here, we're left with a few choices for the addition: if we choose 1+6=7 we're left with 8,9 and 11. We can't write any subtraction with these numbers.

If we choose 1+7=8, we're left with 6, 9 and 11. We can't write any subtraction with these numbers.

If we choose 1+8=9, we're left with 6, 7 and 11. We can't write any subtraction with these numbers.

To recap, we're forced to use 2,3,4,5,10 and 12 for the multiplication and the division, and the remaining numbers don't allow to write an addiction and a subtraction.

Thus, you can't use all the operations involving numbers 1-12 only once.

7 0
3 years ago
Angles A and B are complementary angles in a right triange. The value of cos(A) is 12/13. What is the value of Tan(A)
Orlov [11]
Using the pythagorean identity, we can find the value of sin(A)

cos^2(A) + sin^2(A) = 1
(12/13)^2 + sin^2(A) = 1
144/169 + sin^2(A) = 1
sin^2(A) = 1 - 144/169
sin^2(A) = 169/169 - 144/169
sin^2(A) = (169 - 144)/169
sin^2(A) = 25/169
sin(A) = sqrt(25/169)
sin(A) = 5/13

Which is then used to find tan(A)

tan(A) = sin(A)/cos(A)
tan(A) = (5/13) divided by (12/13)
tan(A) = (5/13)*(13/12)
tan(A) = (5*13)/(13*12)
tan(A) = 5/12

The final answer is 5/12

5 0
3 years ago
Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he
alexgriva [62]

Answer:

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

g(t) = 0

And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

9ty + e^{t}y' = \frac{y}{t^{2} + 81 }

e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t  - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) } ]y = 0

By comparing with y′+p(t)y=g(t), we get

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

g(t) = 0

And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous.

6 0
3 years ago
HIT THE QUANNN AY HIT THE QUANN I SAY GET DOWN LOW AND SPREAD YA ARMS
eduard

Answer:

ok

Step-by-step explanation:

4 0
3 years ago
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